我创建了一个由部分和问题组成的数组。如何循环遍历各个部分并显示每个部分的嵌套问题。
这是我创建数组的方式
$db = db_open();
$query = "SELECT * FROM assessment_selections WHERE assessment_id = '".$annual_assessment["id"]."' AND selection = '1' ORDER BY timestamp ASC";
$result = db_query($db, $query);
$result = db_fetch_all($result);
if (!is_array)
$result = array();
foreach($result as $row) {
$section[$row['section_id']][$row['question_id']] = $row;
}
这是数组
Array
(
[1] => Array // Section 1
(
[1] => Array // Question 1
(
[assessment_selection_id] => 70
[assessment_id] => 32
[section_id] => 1
[question_id] => 1
[selection] => 1
[timestamp] => 1368172762
)
)
[2] => Array // Section 2
(
[3] => Array // Question 3
(
[assessment_selection_id] => 68
[assessment_id] => 32
[section_id] => 2
[question_id] => 3
[selection] => 1
[timestamp] => 1368166250
)
)
[3] => Array // Section 3
(
[4] => Array // Question 4
(
[assessment_selection_id] => 69
[assessment_id] => 32
[section_id] => 3
[question_id] => 4
[selection] => 1
[timestamp] => 1368172690
)
)
[4] => Array // Section 4
(
[5] => Array // Question 5
(
[assessment_selection_id] => 71
[assessment_id] => 32
[section_id] => 4
[question_id] => 5
[selection] => 1
[timestamp] => 1368174153
)
)
)
预期结果(我多么希望能够在 PHP 中回应它们)
第 1 部分
- 问题 1
- 问题 4
- 问题 7
第 2 部分
- 问题 2
- 问题 9
第 3 节
- 问题 3
最佳答案
你应该使用这个循环。
foreach($section as $k=>$section)
{
echo "section $k";
foreach($section as $i=>$question)
{
echo "question $i ".$question['assessment_id']; //more fields available here
}
}
关于php - 在 PHP 中循环遍历数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16477943/