我正在尝试从网站获取一些数据。但是它返回给我incomplete read
。我要获取的数据是大量嵌套链接。我在网上做了一些研究,发现这可能是由于服务器错误(之前完成的分 block 传输编码
达到预期大小)。我还在此 link 上找到了上述解决方法
但是,我不确定如何将其用于我的情况。以下是我正在处理的代码
br = mechanize.Browser()
br.addheaders = [('User-agent', 'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1;Trident/5.0)')]
urls = "http://shop.o2.co.uk/mobile_phones/Pay_Monthly/smartphone/all_brands"
page = urllib2.urlopen(urls).read()
soup = BeautifulSoup(page)
links = soup.findAll('img',url=True)
for tag in links:
name = tag['alt']
tag['url'] = urlparse.urljoin(urls, tag['url'])
r = br.open(tag['url'])
page_child = br.response().read()
soup_child = BeautifulSoup(page_child)
contracts = [tag_c['value']for tag_c in soup_child.findAll('input', {"name": "tariff-duration"})]
data_usage = [tag_c['value']for tag_c in soup_child.findAll('input', {"name": "allowance"})]
print contracts
print data_usage
请帮帮我。谢谢
最佳答案
link您在问题中包含的只是一个执行 urllib 的 read() 函数的包装器,它为您捕获任何不完整的读取异常。如果你不想实现整个补丁,你总是可以在读取链接的地方抛出一个 try/catch 循环。例如:
try:
page = urllib2.urlopen(urls).read()
except httplib.IncompleteRead, e:
page = e.partial
对于python3
try:
page = request.urlopen(urls).read()
except (http.client.IncompleteRead) as e:
page = e.partial
关于python - 如何处理 IncompleteRead : in python,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14442222/