PHP、XML - 获取子节点及其属性

Question

我如何从这个 XML 文件中获取所有“座位”子节点及其属性？

   <seatmap id="1">
      <seat row="A" seatnum="01" available="1" />
      <seat row="A" seatnum="02" available="1" />
      <seat row="A" seatnum="03" available="1" />
      <seat row="A" seatnum="04" available="1" />
      <seat row="A" seatnum="05" available="1" />
    </seatmap>

我有不同的座位图，所以我想通过 ID 查询来获取它们 然后将所有“座位”节点及其属性分配给变量。

到目前为止，我一直在使用 DOM 方法，但也许 simpleXML 或 XPath 会更容易，因为它确实 当您从 DOMDocumet、DOMElement、DOMNode 向下钻取时会感到困惑。

任何帮助都会很棒，干杯!

Answer 1

$XML = <<<XML
<parent>
   <seatmap id="1">
      <seat row="A" seatnum="01" available="1" />
      <seat row="A" seatnum="02" available="1" />
      <seat row="A" seatnum="03" available="1" />
      <seat row="A" seatnum="04" available="1" />
      <seat row="A" seatnum="05" available="1" />
    </seatmap>
</parent>
XML;

$xml_nodes = new SimpleXMLElement($XML);

$nodes = $xml_nodes->xpath('//seatmap[@id = "1"]/seat'); // Replace the ID value with whatever seatmap id you're trying to access

foreach($nodes as $seat)
{
    // You can then access: $seat['row'], $seat['seatnum'], $seat['available']
}