如果我们在python中有一个strings的list，并且想根据一些特殊的string创建子列表，我们应该怎么做？
例如:
l = ["data","more data","","data 2","more data 2","danger","","date3","lll"]
p = split_special(l,"")
会产生:
p = [["data","more data"],["data 2","more data 2","danger"],["date3","lll"]]
最佳答案
itertools.groupby 是一种方法(通常是这样):
>>> l = ["data","more data","","data 2","more data 2","danger","","date3","lll"]
>>> from itertools import groupby
>>> groupby(l, lambda x: x == "")
<itertools.groupby object at 0x9ce06bc>
>>> [list(group) for k, group in groupby(l, lambda x: x == "") if not k]
[['data', 'more data'], ['data 2', 'more data 2', 'danger'], ['date3', 'lll']]
由于这种特殊情况，我们甚至可以作弊:
>>> [list(group) for k, group in groupby(l, bool) if k]
[['data', 'more data'], ['data 2', 'more data 2', 'danger'], ['date3', 'lll']]
关于列表的 Python 拆分，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14529523/