php - Facebook Graph Api 获取链接帖子的图像

Question

我创建了一个简单的小部件来显示来自 Facebook 页面的一篇帖子。这是代码:

//VARS
    $title = $instance['title'];        
    $app_id = $instance['add_id'];
    $app_secret = $instance['app_secret'];
    $page_id = $instance['pade_id'];
    $my_url = $instance['my_url'];
    $page_name = $instance['page_name'];
    $message_lenght = $instance['message_lenght'];

    //CONFIGS
    // get user access_token
    $token_url = 'https://graph.facebook.com/oauth/access_token?client_id='
      . $app_id . '&redirect_uri=' . urlencode($my_url) 
      . '&client_secret=' . $app_secret 
      . '&grant_type=client_credentials';

    // response is of the format "access_token=AAAC..."
    $access_token = substr(file_get_contents($token_url), 13);

    $fql_query_url = 'https://graph.facebook.com/v2.3/' . $page_id
      . '/posts?access_token=' . $access_token;
    $fql_query_result = file_get_contents($fql_query_url);
    $fql_query_obj = json_decode($fql_query_result, true);
    $data = $fql_query_obj['data'][0];

    $img_query_url = 'https://graph.facebook.com/v2.3/' . $data['object_id'] . '/?access_token=' . $access_token;
    $img_query_result = file_get_contents($img_query_url);
    $img_query_obj = json_decode($img_query_result, true);
    $msg = substr($data['message'], 0, $message_lenght). '... ';

    if($img_query_obj['source'] == ""){
        $img_url = $data[picture];
    }else{
        $img_url = $img_query_obj['source'];
    }


    //START APP
    echo $before_widget;

    if($title !== ""){
        echo '<h3>'.$title.'</h3>';
    }   
    ?>
    <div class="facebook-widget">
        <pre class="hide"><?php var_dump($data[picture]); ?></pre>
        <div class="img"><img src="<?php echo $img_url; ?>"></div>
        <div class="text">
            <div class="date">
                FACEBOOK / 
                <?php echo date("m.d.Y", strtotime($data['updated_time'])); ?>
            </div>
            <a class="page_title" target="_blank" href="<?php echo $my_url; ?>">/<?php echo $page_name; ?></a>
            <p><?php echo mb_substr($msg, 0, 95); ?>[...]<a href="<?php echo $data[link]; ?>" target="_blank"> (read more)</a></p>                        
        </div>
        <div class="facebookfollow">
            <a class="facebook-fallow-button" href="<?php echo $my_url; ?>" target="_blank">Follow Us</a>
        </div>
    </div>

    <?php
    echo $after_widget;

如您所见，我添加了条件语句 来检查是否有帖子的照片。 $img_query_obj['source'] 适用于以正常方式发布的帖子 - 一些文本 + 图片上传，其次 - 对于链接的帖子 - 从数据查询中获取 130x130 图片，因为标准方式没有图片。

所以我的问题是，如果响应中只有 130x130 的图片，如何获取帖子图片？

问候

Answer 1

我看到两种方法..它们都不是完美的..

1. 在 w=130&h=130&d=ASDDSA 之间的“图片”链接中...您有 &url= http://some.urlencoded.link.to.picture.jpg - 所以你可以下载它并在旅游服务器上调整大小..

2. 忽略“图片”并获取“链接”——每个链接(http://some.page/article)都是图形对象

https://graph.facebook.com/v2.3/http%3A%2F%2Fstackoverflow.com%2F?access_token=YOUR_TOKEN_HERE

{
   "og_object": {
      "id": "10150180465825637",
      "description": "Q&A for professional and enthusiast programmers",
      "title": "Stack Overflow",
      "type": "website",
      "updated_time": "2015-07-10T22:26:23+0000",
      "url": "http://stackoverflow.com/"
   },
   "share": {
      "comment_count": 11,
      "share_count": 31967
   },
   "id": "http://stackoverflow.com/"
}

作为响应，您将获得 og_objet.id，现在您可以尝试:

https://graph.facebook.com/v2.3/10150180465825637?access_token=YOUR_TOKEN_HERE

{
   "created_time": "2008-04-19T03:48:51+0000",
   "title": "Stack Overflow",
   "type": "website",
   "description": "Q&A for professional and enthusiast programmers",
   "image": [
      {
         "height": 316,
         "url": "http://cdn.sstatic.net/stackoverflow/img/apple-touch-icon\u00402.png?v=ea71a5211a91&a",
         "width": 316
      }
   ],
   "is_scraped": true,
   "updated_time": "2015-07-10T22:26:23+0000",
   "url": "http://stackoverflow.com/",
   "id": "10150180465825637"
}

作为响应，您将获得图片网址，您可以获取图片并调整其大小..