我是 Codeigniter 的新手,我的目标是在学习过程中遵循最佳实践。目前我有一个通过数据库生成的表
HTML 表格
<tr>
<td>
<a class="galName" href="#myModal" data-toggle="modal" >
<?php echo $gal['name']; ?>
</a>
</td>
<td>
<?php echo $gal['clientName']; ?>
</td>
</tr>
<?php endforeach; ?>
模态
<div class="modal fade hide modal-creator" id="myModal" style="display: none;" aria-hidden="true">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h3>Edit Gallery</h3>
</div>
<div class="modal-body"><?php echo form_open('url'); ?>
<div class="row">
<div class="span5">
<?php print_r($galleryName); ?>
<div class="control-group">
<?php
$galleryName = array(
'id' => 'galleryName',
'name' => 'galleryName',
'placeholder' => 'Gallery Name',
'required' => 'required',
);
echo form_label('Gallery Name:', 'galleryName');
echo form_input($galleryName);
?>
</div><!-- /control-group -->
</div><!--/span5-->
</div><!--/row-->
</div><!-- /modal-body -->
<div class="modal-footer">
<!-- <p class="span3 resize">The following images are sized incorrectly. Click to edit</p> -->
<a href="javascript:;" class="btn" data-dismiss="modal">Close</a>
<a href="javascript:;" class="btn btn-primary">Next</a>
</div>
该链接调用了一个 Bootstrap 模式,我想在其中传递所选画廊的数据。我知道我可以通过 jQuery 传递数据,但是是否可以将此模态保留在 MVC 框架中,如果可以,如何通过模态链接调用 Controller ?
非常感谢您的帮助,并且很乐意接受有关 CodeIgniter 资源的任何建议。我目前正在研究 Nettuts 视频,尽管它们已过时,并且还在研究用户指南。
最佳答案
我真的认为您误解了什么是模态和什么是 Controller ,如果没有 ajax 调用,您将无法做到这一点:如何通过模态链接调用 Controller
我通常做的是创建一个 view/modals/
文件夹,然后把我所有的 Bootstrap 模态放在那里,例如:
application/views/modals/my_modal_form.php
这看起来就像你在里面展示的那样:
<div class="modal fade hide modal-creator" id="myModal" style="display: none;" aria-hidden="true">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h3>Edit Gallery</h3>
</div>
<div class="modal-body"><?php echo form_open('url'); ?>
<div class="row">
<div class="span5">
<?php print_r($galleryName); ?>
<div class="control-group">
<?php
$galleryName = array(
'id' => 'galleryName',
'name' => 'galleryName',
'placeholder' => 'Gallery Name',
'required' => 'required',
);
echo form_label('Gallery Name:', 'galleryName');
echo form_input($galleryName);
?>
</div><!-- /control-group -->
</div><!--/span5-->
</div><!--/row-->
</div><!-- /modal-body -->
<div class="modal-footer">
<!-- <p class="span3 resize">The following images are sized incorrectly. Click to edit</p> -->
<a href="javascript:;" class="btn" data-dismiss="modal">Close</a>
<a href="javascript:;" class="btn btn-primary">Next</a>
</div>
所以当我需要那个单一模态时,我只是将它加载到主 Controller View 中,我想简单地显示该模态:
<body>
<?php echo $this->load->view('modals/my_modal_form'); ?>
<tr>
<td>
<a class="galName" href="#myModal" data-toggle="modal" >
<?php echo $gal['name']; ?>
</a>
</td>
<td>
<?php echo $gal['clientName']; ?>
</td>
</tr>
<?php endforeach; ?>
</body>
关于php - Codeigniter - Bootstrap Modal - 传递数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13708010/