我编写了一个非常简单的 Spring MVC 应用程序。抱歉,我是 Spring MVC 的新手,所以请多多包涵。
web.xml如下
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
我的第一个问题是,我有一个使用以下代码登录的 jsp 页面...
<form action="/login" method="post" >
Username : <input name="username" type="text" />
Password : <input name="password" type="password" />
<input type="submit" />
</form>
这给出了 404,但在我的 Controller 中,我已经使用下面的代码将 Controller 映射到/login...
@Controller
public class LoginController {
private static final Logger logger = LoggerFactory.getLogger(LoginController.class);
/**
* Simply selects the home view to render by returning its name.
*/
@RequestMapping(value = "/login", method = RequestMethod.POST)
public String home(Locale locale, Model model, String username, String password) {
if(username.equalsIgnoreCase("david"))
{
logger.info("Welcome home! the client locale is "+ locale.toString());
Date date = new Date();
DateFormat dateFormat = DateFormat.getDateTimeInstance(DateFormat.LONG, DateFormat.LONG, locale);
String formattedDate = dateFormat.format(date);
model.addAttribute("serverTime", formattedDate );
return "home";
}
else
{
return "void";
}
}
}
我的理解是 @requestmapping 应该做 servlet 映射而不是在 web.xml 中,这是正确的吗?如果需要,/WEB-INF/spring/appServlet/servlet-context.xml 的值也显示在下面。
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="org.david.myapp" />
</beans:beans>
所以我的第一个问题是:servlet 映射是在 web.xml 中完成的还是在 Controller 类中的@requestmapping 中完成的?
第二个问题:构建它以拥有更多页面的最佳方法是什么,我应该继续附加到 webxml 吗?我应该为每个网址创建一个 Controller 吗?我应该为每个 url 创建一个 servlet-context 吗?
感谢阅读:)
最佳答案
您已经定义了<url-pattern>
成为/
,这意味着您的 appServlet
将只接收对根 url 的请求。通过将其更改为 /*
appServlet
将获得所有传入的请求。这会起作用,但您也可以考虑创建一个特定的 loginServlet
可以映射到 url /login/*
.
- 您可以在单个
web.xml
中定义多个 servlet .通过添加更多<servlet-mapping>
来指定哪个请求将命中每个 servlet。标签。 - 一个 servlet 可以有很多 Controller 。通常,一个 Controller 服务于您域的特定部分,例如
PersonController
,AddressController
等 - 每个 Controller 通常处理几个逻辑上组合在一起的 url,例如
/persons/{id}
,/persons/search
,/persons/add
等
关于java - SpringMVC servlet映射,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8769145/