我有一个 DataFrame
列名为 date
。我们如何将“日期”列转换/解析为 DateTime
对象?
我使用 sql.read_frame()
从 Postgresql 数据库加载了日期列。 date
列的示例是 2013-04-04
。
我想要做的是选择数据框中的所有行,这些行在特定时期内具有日期列,例如在 2013-04-01
之后和 2013-04- 之前04
.
我在下面的尝试给出了错误 'Series' object has no attribute 'read'
尝试
import dateutil
df['date'] = dateutil.parser.parse(df['date'])
错误
AttributeError Traceback (most recent call last)
<ipython-input-636-9b19aa5f989c> in <module>()
15
16 # Parse 'Date' Column to Datetime
---> 17 df['date'] = dateutil.parser.parse(df['date'])
18
19 # SELECT RECENT SALES
C:\Python27\lib\site-packages\dateutil\parser.pyc in parse(timestr, parserinfo, **kwargs)
695 return parser(parserinfo).parse(timestr, **kwargs)
696 else:
--> 697 return DEFAULTPARSER.parse(timestr, **kwargs)
698
699
C:\Python27\lib\site-packages\dateutil\parser.pyc in parse(self, timestr, default, ignoretz, tzinfos, **kwargs)
299 default = datetime.datetime.now().replace(hour=0, minute=0,
300 second=0, microsecond=0)
--> 301 res = self._parse(timestr, **kwargs)
302 if res is None:
303 raise ValueError, "unknown string format"
C:\Python27\lib\site-packages\dateutil\parser.pyc in _parse(self, timestr, dayfirst, yearfirst, fuzzy)
347 yearfirst = info.yearfirst
348 res = self._result()
--> 349 l = _timelex.split(timestr)
350 try:
351
C:\Python27\lib\site-packages\dateutil\parser.pyc in split(cls, s)
141
142 def split(cls, s):
--> 143 return list(cls(s))
144 split = classmethod(split)
145
C:\Python27\lib\site-packages\dateutil\parser.pyc in next(self)
135
136 def next(self):
--> 137 token = self.get_token()
138 if token is None:
139 raise StopIteration
C:\Python27\lib\site-packages\dateutil\parser.pyc in get_token(self)
66 nextchar = self.charstack.pop(0)
67 else:
---> 68 nextchar = self.instream.read(1)
69 while nextchar == '\x00':
70 nextchar = self.instream.read(1)
AttributeError: 'Series' object has no attribute 'read'
df['date'].apply(dateutil.parser.parse)
给我错误 AttributeError: 'datetime.date' object has no attribute 'read'
df['date'].truncate(after='2013/04/01')
给出错误 TypeError: can't compare datetime.datetime to long
df['date'].dtype
返回 dtype('O')
。它已经是 datetime
对象了吗?
最佳答案
Pandas 知道对象日期时间,但是当您使用某些导入函数时,它会被视为字符串。因此,您需要做的是确保将列设置为日期时间类型而不是字符串。然后,您可以进行查询。
df['date'] = pd.to_datetime(df['date'])
df_masked = df[(df['date'] > datetime.date(2012,4,1)) & (df['date'] < datetime.date(2012,4,4))]
关于python - 从 SQL 数据库导入表并按日期过滤行时,将 Pandas 列解析为 Datetime,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16412099/