java.util.concurrent.DelayQueue 忽略过期元素

标签 java multithreading priority-queue

下面的 java 代码示例使用 java DelayQueue 来处理任务。然而,从另一个线程插入任务似乎会破坏(我的)预期行为。

很抱歉代码示例太长,但总而言之:

  1. 主线程将 5 个任务 (A-E) 添加到具有不同延迟(0 毫秒、10 毫秒、100 毫秒、1000 毫秒、10000 毫秒)的延迟队列
  2. 开始另一个步骤,在 3000 毫秒后将另一个任务添加到 DelayQueue
  3. 主线程轮询 DelayQueue 并在每个 Task 到期时报告
  4. 8000 毫秒后,主线程报告延迟队列中剩余的任务

我从代码示例中得到的输出是:

------initial tasks ---------------
task A due in 0ms
task B due in 9ms
task C due in 99ms
task D due in 999ms
task E due in 9999ms
task F due in 99999ms
------processing--------------------
time = 5    task A due in -1ms
time = 14   task B due in 0ms
time = 104  task C due in 0ms
time = 1004 task D due in 0ms
time = 3003 added task Z due in 0ms
------remaining after 15007ms -----------
task F due in 84996ms
task E due in -5003ms
task Z due in -12004ms

我的问题是:为什么在 15000 毫秒后 DelayQueue 中仍然有过期的任务(即 GetDelay() 返回 -ve 值的地方)?

我检查过的一些东西:

  • 我已经实现了 compareTo() 来定义任务的自然顺序
  • equals() 与compareTo() 一致
  • hashCode() 已被覆盖

我最感兴趣的是了解如何解决这个问题。预先感谢您的协助。 (以及所有那些帮助我约会的 Stack Overflow 答案 :)

    package test;

    import java.util.concurrent.DelayQueue;
    import java.util.concurrent.Delayed;
    import java.util.concurrent.TimeUnit;

    public class Test10_DelayQueue {

       private static final TimeUnit delayUnit = TimeUnit.MILLISECONDS;
       private static final TimeUnit ripeUnit = TimeUnit.NANOSECONDS;

       static long startTime;

       static class Task implements Delayed {    
          public long ripe;
          public String name;    
          public Task(String name, int delay) {
             this.name = name;
             ripe = System.nanoTime() + ripeUnit.convert(delay, delayUnit);
          }

      @Override
      public boolean equals(Object obj) {
         if (obj instanceof Task) {
            return compareTo((Task) obj) == 0;
         }
         return false;
      }

      @Override
      public int hashCode() {
         int hash = 7;
         hash = 67 * hash + (int) (this.ripe ^ (this.ripe >>> 32));
         hash = 67 * hash + (this.name != null ? this.name.hashCode() : 0);
         return hash;
      }

      @Override
      public int compareTo(Delayed delayed) {
         if (delayed instanceof Task) {
            Task that = (Task) delayed;
            return (int) (this.ripe - that.ripe);
         }
         throw new UnsupportedOperationException();
      }

      @Override
      public long getDelay(TimeUnit unit) {
         return unit.convert(ripe - System.nanoTime(), ripeUnit);
      }

      @Override
      public String toString() {
         return "task " + name + " due in " + String.valueOf(getDelay(delayUnit) + "ms");
          }
       }

       static class TaskAdder implements Runnable {

      DelayQueue dq;
      int delay;

      public TaskAdder(DelayQueue dq, int delay) {
         this.dq = dq;
         this.delay = delay;
      }

      @Override
      public void run() {
         try {
            Thread.sleep(delay);

            Task z = new Task("Z", 0);
            dq.add(z);

            Long elapsed = System.currentTimeMillis() - startTime;

            System.out.println("time = " + elapsed + "\tadded " + z);

         } catch (InterruptedException e) {
         }
      }
    }

    public static void main(String[] args) {
      startTime = System.currentTimeMillis();
      DelayQueue<Task> taskQ = new DelayQueue<Task>();

      Thread thread = new Thread(new TaskAdder(taskQ, 3000));
      thread.start();

      taskQ.add(new Task("A", 0));
      taskQ.add(new Task("B", 10));
      taskQ.add(new Task("C", 100));
      taskQ.add(new Task("D", 1000));
      taskQ.add(new Task("E", 10000));
      taskQ.add(new Task("F", 100000));

      System.out.println("------initial tasks ---------------");
      Task[] tasks = taskQ.toArray(new Task[0]);
      for (int i = 0; i < tasks.length; i++) {
         System.out.println(tasks[i]);
      }

      System.out.println("------processing--------------------");
      try {
         Long elapsed = System.currentTimeMillis() - startTime;
         while (elapsed < 15000) {
            Task task = taskQ.poll(1, TimeUnit.SECONDS);
            elapsed = System.currentTimeMillis() - startTime;
            if (task != null) {
               System.out.println("time = " + elapsed + "\t" + task);
            }
         }

         System.out.println("------remaining after " + elapsed + "ms -----------");
         tasks = taskQ.toArray(new Task[0]);
         for (int i = 0; i < tasks.length; i++) {
            System.out.println(tasks[i]);
         }

      } catch (InterruptedException e) {
      }
    }
    }

最佳答案

因为您的comapareTo 方法充满缺陷。正确的实现如下。一旦你像下面这样改变,你所有的问题都会得到解决。如果或遵守 compareTo Contract

,请始终尝试重用 compareTo 方法
return Long.valueOf(this.ripe).compareTo(that.ripe);

关于java.util.concurrent.DelayQueue 忽略过期元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12142025/

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