我想将一个字符串沿非字母字符拆分为一个字符串数组。例如:
"Here is an ex@mple" => "Here", "is", "an" "ex", "mple"
我尝试使用 String.split(String regex)使用正则表达式 "(?![\\p{Alpha}])" 的方法。然而，这会将字符串拆分为
"Here", "_is", "_an", "_ex", "@ample"
(那些下划线是为了强调有一个空格)。我猜这是因为 ?! 正则表达式运算符是“零宽度”的，实际上是拆分和删除输入字符串中非字母字符之前的零宽度字符。
如何在拆分字符串时删除实际的非字母字符？是否存在非零宽度否定运算符？
最佳答案
你可以尝试 \P{Alpha}+:
"Here is an ex@mple".split("\\P{Alpha}+")
["Here", "is", "an", "ex", "mple"]
\P{Alpha} matches any non-alphabetic character (as opposed to \p{Alpha}, which matches any alphabetic character). + indicates that we should split on any continuous string of such characters. For example:
"a!@#$%^&*b".split("\\P{Alpha}+")
["a", "b"]
关于Java 字符串拆分为非字母字符，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13714549/