Python:将类名作为参数传递给函数？

Question

class TestSpeedRetrieval(webapp.RequestHandler):
  """
  Test retrieval times of various important records in the BigTable database 
  """
  def get(self):
      commandValidated = True 
      beginTime = time()
      itemList = Subscriber.all().fetch(1000) 

      for item in itemList: 
          pass 
      endTime = time()
      self.response.out.write("<br/>Subscribers count=" + str(len(itemList)) + 
           " Duration=" + duration(beginTime,endTime)) 

如何将上述内容转换为传递类名的函数？ 在上面的示例中，Subscriber(在 Subscriber.all().fetch 语句中)是一个类名，这是您使用 Python 在 Google BigTable 中定义数据表的方式。

我想做这样的事情:

       TestRetrievalOfClass(Subscriber)  
or     TestRetrievalOfClass("Subscriber")  

谢谢， 尼尔·沃尔特斯

Answer 1

class TestSpeedRetrieval(webapp.RequestHandler):
  """
  Test retrieval times of various important records in the BigTable database 
  """
  def __init__(self, cls):
      self.cls = cls

  def get(self):
      commandValidated = True 
      beginTime = time()
      itemList = self.cls.all().fetch(1000) 

      for item in itemList: 
          pass 
      endTime = time()
      self.response.out.write("<br/>%s count=%d Duration=%s" % (self.cls.__name__, len(itemList), duration(beginTime,endTime))

TestRetrievalOfClass(Subscriber)