我有一个简单的应用程序:
object Test extends App {
implicit def t2mapper[X, X0 <: X, X1 <: X](t: (X0, X1)) = new {
def map[R](f: X => R) = (f(t._1), f(t._2))
}
println("Hello!")
val (foo, bar) = (1, 2) map (_ * 2)
println((foo, bar))
}
(t2mapper
来自 this answer。)
代码编译正常:
$ scalac -version
Scala compiler version 2.9.1 -- Copyright 2002-2011, LAMP/EPFL
$ scalac -unchecked Test.scala
$
但是在运行时,它会抛出一个IllegalAccessError
(之前 Hello!
被打印):
$ java -version java version "1.6.0_24" OpenJDK Runtime Environment (IcedTea6 1.11.1) (6b24-1.11.1-4ubuntu3) OpenJDK Server VM (build 20.0-b12, mixed mode) $ scala Test java.lang.IllegalAccessError: tried to access field Test$.reflParams$Cache1 from class Test$delayedInit$body at Test$delayedInit$body.(Test.scala:6) at Test$.(Test.scala:1) at Test$.(Test.scala) at Test.main(Test.scala) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:616) at scala.tools.nsc.util.ScalaClassLoader$$anonfun$run$1.apply(ScalaClassLoader.scala:78) at scala.tools.nsc.util.ScalaClassLoader$class.asContext(ScalaClassLoader.scala:24) at scala.tools.nsc.util.ScalaClassLoader$URLClassLoader.asContext(ScalaClassLoader.scala:88) at scala.tools.nsc.util.ScalaClassLoader$class.run(ScalaClassLoader.scala:78) at scala.tools.nsc.util.ScalaClassLoader$URLClassLoader.run(ScalaClassLoader.scala:101) at scala.tools.nsc.ObjectRunner$.run(ObjectRunner.scala:33) at scala.tools.nsc.ObjectRunner$.runAndCatch(ObjectRunner.scala:40) at scala.tools.nsc.MainGenericRunner.runTarget$1(MainGenericRunner.scala:56) at scala.tools.nsc.MainGenericRunner.process(MainGenericRunner.scala:80) at scala.tools.nsc.MainGenericRunner$.main(MainGenericRunner.scala:89) at scala.tools.nsc.MainGenericRunner.main(MainGenericRunner.scala)
Note that with the last two lines replaced with
println((1, 2) map (_ * 2))
或
val (foo, bar) = (2, 4)
println((foo, bar))
或
val intermediate = (1, 2) map (_ * 2)
val (foo, bar) = intermediate
println((foo, bar))
它按预期打印 (2,4)
。但是当包裹在一个 block 中时
{
val intermediate = (1, 2) map (_ * 2)
val (foo, bar) = intermediate
println((foo, bar))
}
或
private val blah = {
val intermediate = (1, 2) map (_ * 2)
val (foo, bar) = intermediate
println((foo, bar))
}
它抛出异常。
为什么第一种和最后一种方法会导致 JVM 在运行时抛出错误?
最佳答案
看起来有一些相关的 Unresolved 错误。例如,这一个可能是相关的:
请注意,您也可以创建一个 main
方法而不是扩展 App
,它会起作用。
编辑:
当你使用这一行时(我扩展了隐式):
val (foo, bar) = t2mapper((1, 2)) map (_ * 2)
然后在 Eclipse 中将鼠标悬停在 foo
或 bar
上,它会显示 private[this] val foo
。
因此,它看起来与SI-5251非常相似。
关于java - 为什么这段 Scala 代码会在运行时抛出 IllegalAccessError?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11302291/