谁能给我解释一下下面的场景
待测代码
用户交易.java
@Override
public ServiceResponse<User> get(String name) {
ServiceResponse<User> response = new ServiceResponse<User>();
List<Map<String, Object>> exp = new ArrayList<Map<String, Object>>();
Map<String, Object> map = new HashMap<String, Object>();
map.put("expression", "eq");
map.put("property", "name");
map.put("value", name);
exp.add(map);
List<User> users = userDao.getByCriteria(exp);
if (!users.isEmpty()) {
response.setResponse(users.get(0));
} else {
response.setResponse(null);
}
return response;
}
用户道.java
public List<User> getByCriteria(List<Map<String, Object>> exp) {
DetachedCriteria criteria = DetachedCriteria.forClass(User.class);
for (Integer i=0;i<exp.size();i++){
String expression = (String) exp.get(i).get("expression");
String property = (String) exp.get(i).get("property");
if(expression.equals("eq"){
criteria.add(Restrictions.eq(property,exp.get(i).get("value")));
}
}
return hibernateTemplate.findByCriteria(criteria);
}
UserTransactionTest.java
private UserTransaction userTransactions = new UserTransaction();
private UserDao userDao = mock(UserDao.class);
@Test
public void testGet() {
User user = new User();
user.setName("Raman");
try {
when(userDao.getByCriteria(anyList())).thenReturn(user);
} catch (Exception e) {
e.printStackTrace();
}
ServiceResponse<User> response = userTransactions.get("raman");
User result = response.getResponse();
assertEquals("Raman", result.getName());
assertEquals(0, response.getErrors().size());
}
工作正常。
但我传递的不是“anyList()”,而是一个用户定义的列表“myList”
List<Map<String,Object>> myList = new ArrayList<Map<String,Object>>();
Map<String,Object> map = new HashMap<String,Object>();
map.put("expression","eq");
map.put("property","name");
map.put("value","raman");
myList.add(map);
when(userTransactions.getByCriteria(myList)).thenReturn(user);
在 assertEquals()
行抛出 NullPointerException
。为什么?如果给出 anyList()
,实际会发生什么?
最佳答案
我相信您现在已经解决了您的问题,但如果有人偶然发现同样的问题,这里是答案:
在您提供的代码中,您没有使用模拟的 myList
你创造了。 get()
方法总是调用 userDao.getByCriteria(exp)
, 局部变量。
这就是为什么 anyList()
有效,而myList
没有。
如果您确实想要测试表达式,List<Map<String,Object>> exp
应该是你类(class)的成员,而不是局部变量:
public class UserTransaction {
private List<Map<String,Object>> exp;
public UserTransaction() {
// creating a default exp value
Map<String, Object> map = new HashMap<String, Object>();
map.put("expression", "eq");
map.put("property", "name");
map.put("value", name);
exp.add(map);
}
// getters and setters for exp
public ServiceResponse<User> get(String name) {
ServiceResponse<User> response = new ServiceResponse<User>();
List<User> users = userDao.getByCriteria(exp);
if (!users.isEmpty()) {
response.setResponse(users.get(0));
} else {
response.setResponse(null);
}
return response;
}
}
在你的测试中:
private UserTransaction userTransactions = new UserTransaction();
private UserDao userDao = mock(UserDao.class);
@Test
public void testGet() {
User user = new User();
user.setName("Raman");
// creating a custom expression
List<Map<String,Object>> myList = new ArrayList<Map<String,Object>>();
Map<String,Object> map = new HashMap<String,Object>();
map.put("expression","eq");
map.put("property","name");
map.put("value","raman");
myList.add(map);
// replacing exp with the list created
userTransactions.setExp(myList);
// return user when calling getByCriteria(myList)
when(userDao.getByCriteria(myList)).thenReturn(user);
ServiceResponse<User> response = userTransactions.get("raman");
User result = response.getResponse();
assertEquals("Raman", result.getName());
assertEquals(0, response.getErrors().size());
}
关于java - Junit mockito when(..).thenReturn() 抛出 NullPointerException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11969609/