当我使用 spring v.3.1 执行我的 java 项目时，出现以下错误:
Bean 'configParser'; nested exception is
org.springframework.beans.factory.parsing.BeanDefinitionParsingException: Configuration problem: Unable to locate Spring NamespaceHandler for XML schema namespace [http://www.springframework.org/schema/util]
Offending resource: class path resource [Services.xml]
Bean 'configParser'
我的 POM 有以下依赖:
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>3.1.2.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>3.1.2.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-tx</artifactId>
<version>3.1.2.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-jdbc</artifactId>
<version>3.1.2.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-aop</artifactId>
<version>3.1.2.RELEASE</version>
</dependency>
还有我的 Service.xml 文件:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.1.xsd">
<bean id="configParser" class="com.cc.mp.srv.core.parser.ConfigParser">
<property name="file" >
<util:constant static-field="com.cc.mp.srv.main.Main.FILE_NAME"/>
</property>
</bean>
为什么找不到实用架构？我在 pom 文件中插入核心依赖项。版本号也一样。 什么还需要 Spring？
编辑
Loading schema mappings from [META-INF/spring.schemas]
2015-01-31 18:56:11,553 DEBUG (main) [org.springframework.beans.factory.xml.PluggableSchemaResolver] - Loaded schema mappings: {http://www.springframework.org/schema/tx/spring-tx-2.5.xsd=org/springframework/transaction/config/spring-tx-2.5.xsd, http://www.springframework.org/schema/tx/spring-tx-3.1.xsd=org/springframework/transaction/config/spring-tx-3.1.xsd, http://www.springframework.org/schema/tx/spring-tx-2.0.xsd=org/springframework/transaction/config/spring-tx-2.0.xsd, http://www.springframework.org/schema/tx/spring-tx.xsd=org/springframework/transaction/config/spring-tx-3.1.xsd, http://www.springframework.org/schema/tx/spring-tx-3.0.xsd=org/springframework/transaction/config/spring-tx-3.0.xsd}
如果输出调试消息，则可以识别使用了各种版本号。可能是原因吗？如何定义数字？
我还使用 maven-assembly-plugin 来创建一个可执行的 jar 文件。
最佳答案
架构 http://www.springframework.org/schema/util/spring-util.xsd , http://www.springframework.org/schema/util/spring-util-3.1.xsd (以及带有版本的)带有 spring-beans-<version>.RELEASE.jar
将这个 jar 添加到您的依赖项中:
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-beans</artifactId>
<version>3.1.2.RELEASE</version>
</dependency>
maven-assembly-plugin 的问题:
你写道:
I also use the maven-assembly-plugin to create a executable jar file.
啊...我想 maven-assembly-plugin 是导致该问题的原因。这是因为模式解析机制是这样工作的:Spring 提供带有 jars 的 XSD 文件。在 jar 里，在文件夹 META-INF 中是一个文件schema.info .此文件包含所有 XSD 字段的列表以及此 jar 提供的位置(在 jar 中)。
示例:spring-beans-3.1.1.RELEASE.jar 的 spring.schema
http\://www.springframework.org/schema/beans/spring-beans-2.0.xsd=org/springframework/beans/factory/xml/spring-beans-2.0.xsd
http\://www.springframework.org/schema/beans/spring-beans-2.5.xsd=org/springframework/beans/factory/xml/spring-beans-2.5.xsd
http\://www.springframework.org/schema/beans/spring-beans-3.0.xsd=org/springframework/beans/factory/xml/spring-beans-3.0.xsd
http\://www.springframework.org/schema/beans/spring-beans-3.1.xsd=org/springframework/beans/factory/xml/spring-beans-3.1.xsd
http\://www.springframework.org/schema/beans/spring-beans.xsd=org/springframework/beans/factory/xml/spring-beans-3.1.xsd
http\://www.springframework.org/schema/tool/spring-tool-2.0.xsd=org/springframework/beans/factory/xml/spring-tool-2.0.xsd
http\://www.springframework.org/schema/tool/spring-tool-2.5.xsd=org/springframework/beans/factory/xml/spring-tool-2.5.xsd
http\://www.springframework.org/schema/tool/spring-tool-3.0.xsd=org/springframework/beans/factory/xml/spring-tool-3.0.xsd
http\://www.springframework.org/schema/tool/spring-tool-3.1.xsd=org/springframework/beans/factory/xml/spring-tool-3.1.xsd
http\://www.springframework.org/schema/tool/spring-tool.xsd=org/springframework/beans/factory/xml/spring-tool-3.1.xsd
http\://www.springframework.org/schema/util/spring-util-2.0.xsd=org/springframework/beans/factory/xml/spring-util-2.0.xsd
http\://www.springframework.org/schema/util/spring-util-2.5.xsd=org/springframework/beans/factory/xml/spring-util-2.5.xsd
http\://www.springframework.org/schema/util/spring-util-3.0.xsd=org/springframework/beans/factory/xml/spring-util-3.0.xsd
http\://www.springframework.org/schema/util/spring-util-3.1.xsd=org/springframework/beans/factory/xml/spring-util-3.1.xsd
http\://www.springframework.org/schema/util/spring-util.xsd=org/springframework/beans/factory/xml/spring-util-3.1.xsd
现在你有不同的 jar ( spring-beans , spring-tx , spring-aop , spring-context ...)，它们都包含一个 META-INF/spring.schemas文件，内容不同。另一方面，您使用 maven-assembly-plugin将所有 jar 文件的内容聚合到一个文件中。
我猜你会遇到 spring.handlers 的问题文件也是。
看起来你可以配置 maven-assembly-plugin合并这些文件。参见:this answer的 How can I merge resource files in a Maven assembly?
另一种解决方案是使用 spring-boot-maven-plugin而不是 maven-assembly-plugin
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
<version>1.2.1</version>
<executions>
<execution>
<goals>
<goal>repackage</goal>
</goals>
</execution>
</executions>
<configuration>
<mainClass>YOUR.MAIN.CLASS</mainClass>
</configuration>
</plugin>
(或使用 maven-shade-pluging )
关于java - 无法找到 Spring NamespaceHandler util，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/28254417/