我知道将 JSON 字符串转换为 Map<String, String>
的实现通过:
public <T1, T2> HashMap<T1, T2> getMapFromJson(String json, Class<T1> keyClazz, Class<T2> valueClazz) throws TMMIDConversionException {
if (StringUtils.isEmpty(json)) {
return null;
}
try {
ObjectMapper mapper = getObjectMapper();
HashMap<T1, T2> map = mapper.readValue(json, TypeFactory.defaultInstance().constructMapType(HashMap.class, keyClazz, valueClazz));
return map;
} catch (Exception e) {
Logger.error(e.getMessage(), e.getCause());
}
}
但我无法扩展它以将我的 JSON 转换为 Map<String, Set<String>>
.显然,上述方法失败了,因为它破坏了 Set 项并放入列表中。这里需要一些帮助!!谢谢
示例 JSON 字符串如下。此 JSOn 必须转换为 Map<String, Set<CustomClass>>
.
{
"0": [
{
"cid": 100,
"itemId": 0,
"position": 0
}
],
"1": [
{
"cid": 100,
"itemId": 1,
"position": 0
}
],
"7": [
{
"cid": 100,
"itemId": 7,
"position": -1
},
{
"cid": 140625,
"itemId": 7,
"position": 1
}
],
"8": [
{
"cid": 100,
"itemId": 8,
"position": 0
}
],
"9": [
{
"cid": 100,
"itemId": 9,
"position": 0
}
]
}
最佳答案
试试这个:
JavaType setType = mapper.getTypeFactory().constructCollectionType(Set.class, CustomClass.class);
JavaType stringType = mapper.getTypeFactory().constructType(String.class);
JavaType mapType = mapper.getTypeFactory().constructMapType(Map.class, stringType, setType);
String outputJson = mapper.readValue(json, mapType)
关于java - 如何使用 Jackson JSON 将 JSON 字符串转换为 Map<String, Set<String>>,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27523186/