java - 如何在 Netbeans 平台上获取项目类型？

Question

有没有办法知道所选项目的类型？我想根据项目类型(如 J2SE 项目)执行一些特定操作。

以下是我发现的唯一方法:

public final class MyAction extends CookieAction { 

@Override 
public boolean isEnabled() { 
  if(this.getActivatedNodes() == null || this.getActivatedNodes().length != 1) { 
        return false; 
    } 

    Lookup lookup = this.getActivatedNodes()[0].getLookup(); 

    // gets the selected project 
    Project currentProject = lookup.lookup(Project.class); 

    // checks if the selected project is a J2SE Project or a Maven Project 
    if(currentProject != null && (currentProject.getClass().getSimpleName().equals("J2SEProject") 
            || currentProject.getClass().getSimpleName().equals("NbMavenProjectImpl"))) { 
        return true; 
    } 

    return false;

}}

Answer 1

简单的 new -> action -> conditionaly enabled (Project) 就可以了。

 package project.action;

import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
import org.netbeans.api.project.Project;

import org.openide.awt.ActionRegistration;
import org.openide.awt.ActionReference;
import org.openide.awt.ActionReferences;
import org.openide.awt.ActionID;
import org.openide.util.NbBundle.Messages;

@ActionID(category = "Build",
id = "project.action.SomeAction")
@ActionRegistration(displayName = "#CTL_SomeAction")
@ActionReferences({
    @ActionReference(path = "Menu/File", position = 0)
})
@Messages("CTL_SomeAction=SomeAction")
public final class SomeAction implements ActionListener {

private final Project context;

public SomeAction(Project context) { // this is enable !!
    this.context = context;
}

public void actionPerformed(ActionEvent ev) {
    // TODO use context
}
}

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