我正在为 Cisco CMX device 使用 REST API ,并尝试编写 Python 代码向 API 发出 GET 请求以获取信息。代码如下,与文件中的代码相同,只是必要的信息有所改变。
from http.client import HTTPSConnection
from base64 import b64encode
# Create HTTPS connection
c = HTTPSConnection("0.0.0.0")
# encode as Base64
# decode to ascii (python3 stores as byte string, need to pass as ascii
value for auth)
username_password = b64encode(b"admin:password").decode("ascii")
headers = {'Authorization': 'Basic {0}'.format(username_password)}
# connect and ask for resource
c.request('GET', '/api/config/v1/aaa/users', headers=headers)
# response
res = c.getresponse()
data = res.read()
但是,我不断收到以下错误:
Traceback (most recent call last):
File "/Users/finaris/PycharmProjects/test/test/test.py", line 14, in <module>
c.request('GET', '/api/config/v1/aaa/users', headers=headers)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/http/client.py", line 1106, in request
self._send_request(method, url, body, headers)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/http/client.py", line 1151, in _send_request
self.endheaders(body)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/http/client.py", line 1102, in endheaders
self._send_output(message_body)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/http/client.py", line 934, in _send_output
self.send(msg)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/http/client.py", line 877, in send
self.connect()
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/http/client.py", line 1260, in connect
server_hostname=server_hostname)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/ssl.py", line 377, in wrap_socket
_context=self)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/ssl.py", line 752, in __init__
self.do_handshake()
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/ssl.py", line 988, in do_handshake
self._sslobj.do_handshake()
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/ssl.py", line 633, in do_handshake
self._sslobj.do_handshake()
ssl.SSLError: [SSL: TLSV1_ALERT_PROTOCOL_VERSION] tlsv1 alert protocol version (_ssl.c:645)
我也尝试更新 OpenSSL,但没有效果。
最佳答案
我遇到了同样的错误,谷歌把我带到了这个问题,所以这就是我所做的,希望它可以帮助遇到类似情况的其他人。
这适用于 OS X。
在终端中检查我拥有的 OpenSSL 版本:
$ python3 -c "import ssl; print(ssl.OPENSSL_VERSION)"
>> OpenSSL 0.9.8zh 14 Jan 2016
由于我的 OpenSSL 版本太旧,因此接受的答案不起作用。
所以我不得不更新 OpenSSL。为此,我使用 Homebrew 将 Python 更新到最新版本(从 3.5 版到 3.6 版),遵循建议的一些步骤 here :
$ brew update
$ brew install openssl
$ brew install python3
然后我遇到了 PATH 和正在使用的 python 版本的问题,所以我创建了一个新的 virtualenv
以确保采用最新版本的 python:
$ virtualenv webapp --python=python3.6
问题已解决。
关于python - ssl.SSLError : tlsv1 alert protocol version,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44316292/