java - 如何更改 Hibernate CharacterTypeDescriptor 以处理空列值

标签 java hibernate jpa hibernate-mapping

我们的问题是由于源自 Hibernate 的 字符类型描述符。我们想更改 Hibernate 的行为以正确解析空字符串。

示例数据:

1, 'Berlin', 17277, '', 'aUser'
2, 'London', 17277, '', 'anotherUser'

我们将 hibernate 与 javax.persistence.Query 结合使用。

String sql = "SELECT * FROM table";
Query query = entityManager.createNativeQuery(sql);
List resultList = query.getResultList();

这会导致 StringIndexOutOfBoundsException,其根是来自 Hibernate 的以下代码:

if ( String.class.isInstance( value ) ) {
   final String str = (String) value;
   return Character.valueOf( str.charAt(0) );  // this fails, as there is no char at position 0
}

a post on the hibernate forums 证实了这一点.

我们无法从这个有问题的版本升级 hibernate 并寻找一种方法来更改 Hibernate 的映射。

我们不能使用 PreparedStatements 或普通的 JDBC-Connections 或 JPA-Entities。

改变遗留数据库也是不可能的。 SQL 语句使用 DBVisualizer 完美运行。

有没有办法改变Hibernate映射字符串的方式?

最佳答案

The CharacterType presented in this answer is available via the hibernate-types project, so there is no need to write it yourself.

首先,你需要定义一个ImmutableType:

public abstract class ImmutableType<T> implements UserType {

    private final Class<T> clazz;

    protected ImmutableType(Class<T> clazz) {
        this.clazz = clazz;
    }

    @Override
    public Object nullSafeGet(
        ResultSet rs, 
        String[] names,
        SharedSessionContractImplementor session, 
        Object owner) 
        throws SQLException {
        return get(rs, names, session, owner);
    }

    @Override
    public void nullSafeSet(
        PreparedStatement st, 
        Object value, 
        int index,
        SharedSessionContractImplementor session) 
        throws SQLException {
        set(st, clazz.cast(value), index, session);
    }

    protected abstract T get(
        ResultSet rs, 
        String[] names,
        SharedSessionContractImplementor session, 
        Object owner) throws SQLException;

    protected abstract void set(
        PreparedStatement st, 
        T value, 
        int index,
        SharedSessionContractImplementor session) 
        throws SQLException;


    @Override
    public Class<T> returnedClass() {
        return clazz;
    }

    @Override
    public boolean equals(Object x, Object y) {
        return Objects.equals(x, y);
    }

    @Override
    public int hashCode(Object x) {
        return x.hashCode();
    }

    @Override
    public Object deepCopy(Object value) {
        return value;
    }

    @Override
    public boolean isMutable() {
        return false;
    }

    @Override
    public Serializable disassemble(Object o) {
        return (Serializable) o;
    }

    @Override
    public Object assemble(
        Serializable cached, 
        Object owner) {
        return cached;
    }

    @Override
    public Object replace(
        Object o, 
        Object target, 
        Object owner) {
        return o;
    }
}

现在,我们可以开始定义实际的 CharacterType:

public class CharacterType 
    extends ImmutableType<Character> {

    public CharacterType() {
        super(Character.class);
    }

    @Override
    public int[] sqlTypes() { 
        return new int[]{Types.CHAR}; 
    }

    @Override
    public Character get(
        ResultSet rs, 
        String[] names,
        SharedSessionContractImplementor session, 
        Object owner) 
        throws SQLException {
        String value = rs.getString(names[0]);
        return (value != null && value.length() > 0) ? 
            value.charAt(0) : null;
    }

    @Override
    public void set(
        PreparedStatement st, 
        Character value, 
        int index,
        SharedSessionContractImplementor session) 
        throws SQLException {
        if (value == null) {
            st.setNull(index, Types.CHAR);
        } else {
            st.setString(index, String.valueOf(value));
        }
    }
}

实体映射如下所示:

@Entity(name = "Event")
@Table(name = "event")
public class Event {

    @Id
    @GeneratedValue
    private Long id;

    @Type(type = "com.vladmihalcea.book.hpjp.hibernate.type.CharacterType")
    @Column(name = "event_type")
    private Character type;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public Character getType() {
        return type;
    }

    public void setType(Character type) {
        this.type = type;
    }
}

假设我们有这些表行:

INSERT INTO event (id, event_type) VALUES (1, 'abc');    
INSERT INTO event (id, event_type) VALUES (2, '');
INSERT INTO event (id, event_type) VALUES (3, 'b');

读取所有实体时:

doInJPA(entityManager -> {
    List<Event> events = entityManager.createQuery(
        "select e from Event e", Event.class)
    .getResultList();
    for(Event event : events) {
        LOGGER.info("Event type: {}", event.getType());
    }
});

您将获得预期的输出:

Event type: a
Event type:  
Event type: b

GitHub 上查看源代码.

关于java - 如何更改 Hibernate CharacterTypeDescriptor 以处理空列值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39615788/

相关文章:

java - 如何在 Hibernate 中使用@Subselect

java - Spring中的事务错误

java - 如何访问jpa中的多对多表?

java - 不使用 Oracle jar 的 WebLogic 客户端

java - 通过布局充气器设置复选框 setChecked()

java - session.save 不返回持久化对象,只返回标识符

java - "Delete Where"在 Hibernate 中级联删除?

java - AES 256 文本加密返回不同的值

java - Java 的 LinkedHashMap 是否维护键的顺序?

java - JPA 1 不够好