java - 如何将字符从 Oracle 编码为 XML？

Question

在我这里的环境中，我使用 Java 将结果集序列化为 XML。 它基本上是这样发生的:

//foreach column of each row
xmlHandler.startElement(uri, lname, "column", attributes);
String chars = rs.getString(i);
xmlHandler.characters(chars.toCharArray(), 0, chars.length());
xmlHandler.endElement(uri, lname, "column");

XML 在 Firefox 中看起来像这样:

<row num="69004">
    <column num="1">10069</column>
    <column num="2">sd&#26;</column>
    <column num="3">FCVolume                      </column>
</row>

但是当我解析 XML 时，我得到了一个

org.xml.sax.SAXParseException: Character reference "&#26" is an invalid XML character.

我现在的问题是:我必须替换哪些字符，或者我必须如何对我的字符进行编码，使它们成为有效的 XML？

Answer 1

我在 Xml Spec 中发现了一个有趣的列表: 根据该列表，不鼓励使用字符 #26(十六进制:#x1A)。

The characters defined in the following ranges are also discouraged. They are either control characters or permanently undefined Unicode characters

参见 complete ranges .

此代码替换字符串中所有无效的 Xml Utf8:

public String stripNonValidXMLCharacters(String in) {
    StringBuffer out = new StringBuffer(); // Used to hold the output.
    char current; // Used to reference the current character.

    if (in == null || ("".equals(in))) return ""; // vacancy test.
    for (int i = 0; i < in.length(); i++) {
        current = in.charAt(i);
        if ((current == 0x9) ||
            (current == 0xA) ||
            (current == 0xD) ||
            ((current >= 0x20) && (current <= 0xD7FF)) ||
            ((current >= 0xE000) && (current <= 0xFFFD)) ||
            ((current >= 0x10000) && (current <= 0x10FFFF)))
            out.append(current);
    }
    return out.toString();
}    

取自Invalid XML Characters: when valid UTF8 does not mean valid XML

但是我仍然遇到 UTF-8 兼容性问题:

org.xml.sax.SAXParseException: Invalid byte 1 of 1-byte UTF-8 sequence

看完XML - returning XML as UTF-8 from a servlet我只是尝试了如果我这样设置 Contenttype 会发生什么:

response.setContentType("text/xml;charset=utf-8");

它奏效了....