如何将 xml 文件转换为简单的 java bean? 它是一个没有任何 xsd 的简单 xml 文件,它是从我无权访问的 java bean 生成的。
我尝试使用 xmlbeans 首先从 xml 生成 xmd,然后从 xsd 生成类。我有很多类(class)。我正在寻找单个 java bean 类。
最佳答案
JAXB
JAXB ( JSR-222 ) 提供了一种将对象转换为 XML 的简单方法。该标准有许多开源实现,包括:
- Metro JAXB (Java SE 6 中包含的引用实现)
- EclipseLink JAXB (MOXy) , 我是技术主管
- Apache JaxMe
JAXB 有一个默认的 Java 对象到 XML 的映射。可以通过应用注释来自定义此映射。
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.Element;
@XmlRootElement
public class Address {
private String street;
private String city;
private String state;
private String country;
@XmlElement(name="postal-code")
private String postalCode;
}
将对应于以下 XML:
<address>
<street>123 A Street</street>
<city>Any Town</city>
<state>A State</state>
<postal-code>12345</postal-code>
</address>
EclipseLink JAXB (MOXy)
MOXy 有一个基于 XPath 的映射扩展。这意味着我们可以采用相同的地址类并将其映射到 Google 的地理编码格式:
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
import org.eclipse.persistence.oxm.annotations.XmlPath;
@XmlRootElement(name="kml")
@XmlType(propOrder={"country", "state", "city", "street", "postalCode"})
public class Address {
@XmlPath("Response/Placemark/ns:AddressDetails/ns:Country/ns:AdministrativeArea/ns:SubAdministrativeArea/ns:Locality/ns:Thoroughfare/ns:ThoroughfareName/text()")
private String street;
@XmlPath("Response/Placemark/ns:AddressDetails/ns:Country/ns:AdministrativeArea/ns:SubAdministrativeArea/ns:Locality/ns:LocalityName/text()")
private String city;
@XmlPath("Response/Placemark/ns:AddressDetails/ns:Country/ns:AdministrativeArea/ns:AdministrativeAreaName/text()")
private String state;
@XmlPath("Response/Placemark/ns:AddressDetails/ns:Country/ns:CountryNameCode/text()")
private String country;
@XmlPath("Response/Placemark/ns:AddressDetails/ns:Country/ns:AdministrativeArea/ns:SubAdministrativeArea/ns:Locality/ns:PostalCode/ns:PostalCodeNumber/text()")
private String postalCode;
}
上述类对应以下XML:
<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://earth.google.com/kml/2.0" xmlns:ns="urn:oasis:names:tc:ciq:xsdschema:xAL:2.0">
<Response>
<Placemark>
<ns:AddressDetails>
<ns:Country>
<ns:CountryNameCode>US</ns:CountryNameCode>
<ns:AdministrativeArea>
<ns:AdministrativeAreaName>CA</ns:AdministrativeAreaName>
<ns:SubAdministrativeArea>
<ns:Locality>
<ns:LocalityName>Mountain View</ns:LocalityName>
<ns:Thoroughfare>
<ns:ThoroughfareName>1600 Amphitheatre Pkwy</ns:ThoroughfareName>
</ns:Thoroughfare>
<ns:PostalCode>
<ns:PostalCodeNumber>94043</ns:PostalCodeNumber>
</ns:PostalCode>
</ns:Locality>
</ns:SubAdministrativeArea>
</ns:AdministrativeArea>
</ns:Country>
</ns:AddressDetails>
</Placemark>
</Response>
</kml>
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关于java - 将 xml 转换为 java bean,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5827713/