一旦在此代码中捕获到异常,menuSystem
方法就会运行,但是一旦我输入数字,程序就会关闭并显示“构建成功”消息。一旦发生异常,有没有办法回到 while 循环?
public static void main(String[] args) {
final UnitResults myUnit = new UnitResults(10, "Java");
int option = menuSystem();
try {
while (option != 0) {
final Scanner keyb = new Scanner(System.in);
System.out.println("");
switch (option) {
}
}
} catch (Exception InputMismachException) {
System.out.println("\nPlease Enter a Valid Number\n");
option = menuSystem();
}
}
最佳答案
将您的 try/catch 放入您的 while 循环:
while (option != 0) {
final Scanner keyb = new Scanner(System.in);
System.out.println("");
try {
switch (option) {
}
} catch (Exception InputMismachException) {
System.out.println("\nPlease Enter a Valid Number\n");
option = menuSystem();
}
}
关于java - try/catch 捕获异常后继续执行循环,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13805008/