我在将我的 java 应用程序连接到我的 SignalR 服务器时遇到问题。
服务器非常简单,可以在这里找到:
https://code.msdn.microsoft.com/windowsdesktop/Using-SignalR-in-WinForms-f1ec847b
我可以连接web 客户端(javascript) 和windows 客户端(C#) 但是我的java 客户端有问题。( https://github.com/SignalR/java-client )
到目前为止,这是我的代码:
package javaapplication2;
import java.io.IOException;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.TimeoutException;
import microsoft.aspnet.signalr.client.SignalRFuture;
import microsoft.aspnet.signalr.client.hubs.HubConnection;
import microsoft.aspnet.signalr.client.hubs.HubProxy;
public class JavaApplication2 {
public static void main(String[] args) throws IOException, InterruptedException, ExecutionException, TimeoutException
{
String ServerURI = "http://localhost:8080/signalr";
HubConnection Connection = new HubConnection(ServerURI);
HubProxy HubProxy = Connection.createHubProxy("MyHub");
HubProxy.on("AddMessage", () -> { System.out.println("Some message"); });
Connection.error(new ErrorCallback() {
@Override
public void onError(Throwable error) {
error.printStackTrace(); //<==SocketException
}
});
SignalRFuture<Void> con =Connection.start();
con.get();
}
}
更新
当我运行它时,我得到一个“ExecutionException: java.net.SocketException: Connection reset”
Exception in thread "main" java.util.concurrent.ExecutionException: java.net.SocketException: Connection reset
at microsoft.aspnet.signalr.client.SignalRFuture.get(SignalRFuture.java:112)
at microsoft.aspnet.signalr.client.SignalRFuture.get(SignalRFuture.java:102)
at javaapplication2.JavaApplication2.main(JavaApplication2.java:27)
Caused by: java.net.SocketException: Connection reset
at java.net.SocketInputStream.read(SocketInputStream.java:209)
at java.net.SocketInputStream.read(SocketInputStream.java:141)
at java.io.BufferedInputStream.fill(BufferedInputStream.java:246)
at java.io.BufferedInputStream.read1(BufferedInputStream.java:286)
at java.io.BufferedInputStream.read(BufferedInputStream.java:345)
at sun.net.www.http.HttpClient.parseHTTPHeader(HttpClient.java:704)
at sun.net.www.http.HttpClient.parseHTTP(HttpClient.java:647)
at sun.net.www.http.HttpClient.parseHTTP(HttpClient.java:675)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1535)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1440)
at java.net.HttpURLConnection.getResponseCode(HttpURLConnection.java:480)
at microsoft.aspnet.signalr.client.http.java.NetworkRunnable.run(NetworkRunnable.java:72)
at java.lang.Thread.run(Thread.java:745)
-如果我将“localhost”更改为不存在的内容(例如 locahostX),我会得到一个 java.net.UnknownHostException
-如果将“localhost”更改为我的 IP,我不会遇到异常...
-所有其他应用程序都可以同时使用(本地主机或 IP)
起初我以为是防火墙问题,但不是...
显然我错过了一些东西...... 有什么想法吗?
谢谢
最佳答案
事实证明,我必须使用 start 的重载,即以 ClientTransport 对象作为参数的重载
public SignalRFuture<Void> start(ClientTransport transport)
如果有人能解释无参数启动方法失败的原因,请将其作为答案发布,我会将其标记为解决方案。
这是一个完整的例子:
package javaapplication2;
import java.io.IOException;
import java.util.Scanner;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.TimeoutException;
import microsoft.aspnet.signalr.client.SignalRFuture;
import microsoft.aspnet.signalr.client.hubs.HubConnection;
import microsoft.aspnet.signalr.client.hubs.HubProxy;
import microsoft.aspnet.signalr.client.transport.ServerSentEventsTransport;
import microsoft.aspnet.signalr.client.hubs.SubscriptionHandler2;
public class JavaApplication2 {
public static void main(String[] args) throws IOException, InterruptedException, ExecutionException, TimeoutException
{
String ServerURI = "http://localhost:8080/signalr";
HubConnection Connection = new HubConnection(ServerURI);
HubProxy HubProxy = Connection.createHubProxy("MyHub");
HubProxy.on("AddMessage", new SubscriptionHandler2<String, String>() {
@Override
public void run(String e1, String e2) {
System.out.println(e1.toString()+ " -> " +e2.toString());
}
}, String.class, String.class);
SignalRFuture<Void> con =Connection.start(new ServerSentEventsTransport(Connection.getLogger())); //Or LongPollingTransport
con.get();
Scanner inputReader = new Scanner(System.in);
String line = inputReader.nextLine();
while (!"exit".equals(line)) {
HubProxy.invoke("send", "Console", line);
line = inputReader.next();
}
inputReader.close();
Connection.stop();
}
}
关于java - SignalR java 无法连接到服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30263847/