Java:使用 HTTPBasic 身份验证获取 URL

Question

我正在做一些简单的 HTTP 身份验证并得到一个

java.lang.IllegalArgumentException: Illegal character(s) in message header value: Basic OGU0ZTc5ODBk(...trimmed from 76 chars...)
(...more password data...)

我认为这是因为我有一个非常长的用户名和密码，并且编码器用 76 个字符的 \n 将其包装起来。有什么办法可以解决这个问题吗？该 URL 仅支持 HTTP 基本身份验证。

这是我的代码:

private class UserPassAuthenticator extends Authenticator {
    String user;
    String pass;
    public UserPassAuthenticator(String user, String pass) {
        this.user = user;
        this.pass = pass;
    }

    // This method is called when a password-protected URL is accessed
    protected PasswordAuthentication getPasswordAuthentication() {
        return new PasswordAuthentication(user, pass.toCharArray());
    }
}

private String fetch(StoreAccount account, String path) throws IOException {
    Authenticator.setDefault(new UserPassAuthenticator(account.getCredentials().getLogin(), account.getCredentials().getPassword()));

    URL url = new URL("https", account.getStoreUrl().replace("http://", ""), path);
    System.out.println(url);

    URLConnection urlConn = url.openConnection();
    Object o = urlConn.getContent();
    if (!(o instanceof String)) 
        throw new IOException("Wrong Content-Type on " + url.toString());

    // Remove the authenticator back to the default
    Authenticator.setDefault(null);
    return (String) o;
}

Answer 1

这似乎是一个 bug in Java .

您是否尝试过使用其他 HTTP 客户端，例如来自 Apache 的库？

或者不使用 Authenticator，而是手动设置 header ？

URL url = new URL("http://www.example.com/");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("Authorization", "Basic OGU0ZTc5ODBkABcde....");

token 值为 encodeBase64("username:password")。