我有一个 Java 文件
FileInputStream in = null;
try{
in = new FileInputStream("C:\\pic.bmp");
}catch{}
我想将 pic.bmp 转换为十六进制值数组,以便我可以编辑并将其保存为修改后的版本。
是否有 java 类来执行此操作?
最佳答案
你很幸运。几个月前我不得不这样做。这是一个从命令行获取两个参数的简化版本。两个命令行参数都是文件名...第一个是输入文件,第二个是输出文件。输入文件以二进制形式读取,输出文件以 ASCII 十六进制形式写入。希望您可以根据自己的需要进行调整。
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.IOException;
public class BinToHex
{
private final static String[] hexSymbols = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "a", "b", "c", "d", "e", "f" };
public final static int BITS_PER_HEX_DIGIT = 4;
public static String toHexFromByte(final byte b)
{
byte leftSymbol = (byte)((b >>> BITS_PER_HEX_DIGIT) & 0x0f);
byte rightSymbol = (byte)(b & 0x0f);
return (hexSymbols[leftSymbol] + hexSymbols[rightSymbol]);
}
public static String toHexFromBytes(final byte[] bytes)
{
if(bytes == null || bytes.length == 0)
{
return ("");
}
// there are 2 hex digits per byte
StringBuilder hexBuffer = new StringBuilder(bytes.length * 2);
// for each byte, convert it to hex and append it to the buffer
for(int i = 0; i < bytes.length; i++)
{
hexBuffer.append(toHexFromByte(bytes[i]));
}
return (hexBuffer.toString());
}
public static void main(final String[] args) throws IOException
{
try
{
FileInputStream fis = new FileInputStream(new File(args[0]));
BufferedWriter fos = new BufferedWriter(new FileWriter(new File(args[1])));
byte[] bytes = new byte[800];
int value = 0;
do
{
value = fis.read(bytes);
fos.write(toHexFromBytes(bytes));
}while(value != -1);
fos.flush();
fos.close();
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
关于Java:文件到十六进制?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1314568/