java - 从 Apache Commons HTTP 请求获取页面内容

Question

所以我正在使用 Apache Commons HTTP 向网页发出请求。我一辈子都弄不明白如何从页面中获取实际内容，我只能获取其标题信息。如何从中获取实际内容？

这是我的示例代码:

HttpGet request = new HttpGet("http://URL_HERE/");

HttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(request);

System.out.println("Response: " + response.toString());

Answer 1

BalusC 的评论会很好用。 如果您使用的是 Apache HttpComponents 的版本 4 或更新版本，您还可以使用一种便捷的方法: EntityUtils.toString(HttpEntity);

这是您的代码中的样子:

HttpGet request = new HttpGet("http://URL_HERE/");
HttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute(request);
HttpEntity entity = response.getEntity();
String entityContents = EntityUtils.toString(entity);

不确定这是不是因为版本不同，但我不得不这样重写:

HttpGet request = new HttpGet("http://URL_HERE/");
CloseableHttpClient httpClient = HttpClients.createDefault();
HttpResponse response = httpClient.execute(request);
HttpEntity entity = response.getEntity();
String entityContents = EntityUtils.toString(entity);