java - 专有 XML 文件(Roche LC480 .ixo 文件)中的二进制字段编码/序列化格式

标签 java serialization encoding mfc binary-data

我最近收到了一个由 Roche LightCycler 480 仪器生成的示例导出文件。它使用专有的 XML 格式,对此我还没有找到规范。

从这些类型的文件中,我想提取一些与我的目的相关的信息。尽管其中大部分都可以轻松解析和解释,但它包含许多(未填充的)base 64 编码的二进制/序列化数据字段,表示整数和/或浮点数数组。示例文件的链接可以在 this gist 中找到。 .

我在这篇文章的末尾包含了它的一些片段。 AcquisitionTable共包含19此类编码 item条目。这可能代表整数( SampleNo )和浮点( Fluor1 )值的数组。

我仍然不清楚如何将解码的字节转换为整数或浮点值。当 base 64 解码时,每个项目都以以下(十六进制)6 字节序列开头:

42 41 52 5A 00 00 ...    // ['B','A','R','Z','\0','\0', ...]

请注意,虽然我期望每个“项目”包含相同数量的数字(或此表中的“行”),但我观察到类似项目的解码字节数不同:5654 表示 Fluor1和 5530 为 Fluor2 .

此外,对于那些我怀疑包含(顺序)整数的数组,可以观察到一个模式:
SampleNo : ... 1F F5 1F 07 2F 19 2F 2B 2F 3D 2F 4F 2F 61 2F 00 73 2F 85 2F 97 2F A9 2F BB 2F CD 2F DF 2F F1 2F 00 03 3F 15 3F 27 ...
Cycles   : ... 1F FF 1F 11 2F 23 2F 35 2F 47 2F 59 2F 6B 2F 00 7D 2F 8F 2F A1 2F B3 2F C5 2F D7 2F E9 2F FB 2F 00 0D 3F 1F 3F 31 ...
Gain     : ... 1F EE 1F 00 2F 12 2F 24 2F 36 2F 00 48 2F 5A 2F 6C 2F 7E 2F 90 2F A2 2F B4 2F C6 2F 00 D8 2F EA 2F FC 2F 0E 3F 20 3F 32 ...

它看起来像字节对,其中第二个字节增加了 0x12 (18) 偶尔还有一组 3 个字节,带有 0x00作为第二个字节,以防最后一个字节的半字节是 3 , D8分别为三个例子。

我想知道编码/序列化格式的类型是否对任何人都是显而易见的(或者,如果有人有这种文件格式的规范,那就更好了)。

我相信用于创建这些文件的软件目前是基于 Java 的,但作为 Windows/MFC/C++ 产品的历史。
<obj name="AcquisitionTable" class="AcquisitionTable" version="1">
    <prop name="Count">2400</prop>
    <prop name="ChannelCount">6</prop>
    <list name="Columns" count="19">
        <item name="SampleNo">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</item>
        <item name="ProgramNo">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</item>

... 剪断
        <item name="Fluor1">QkFSWgAAFg0CAFYJ+xwg7vGsP1qIWb738CFAHegc//CsnT/u9cqGyQ8A/PcbfVgeAas/qoOpJwDu/P9SgVE/ACFAHmuwHUcArR0GwX9WAWYUD2l9bgFcD9l7hgFmdA9Jep4BLA8pd7YBZqQPmXXOAYwP0XTmAWa8D0Fz/gHsD7FxFhFmBB9Zby4RHB8BbUYRZjQfqWpeEUwfGWl2EWZkH8FmjhHUD2lkphFmfB8RYr4RlB+5X9YRZqwf8V7uEdwfmVwGIWb0H0FaHiEML+lXNiFmxB+RVU4hPC9xUmYhZiQv4VB+IVQviU6WIWZsL2lLriGcL0lIxiFmtC+5Rt4hzC+ZQ/YhMoQvQQ4y/C8hPiYy/f4zkTw+MRQ/cTlWMUQ/M+E3bjFcP4k1hjF0PzMxM54xLD/ZMLYxpD8zSS/OMYw/KSzmMbw/M5kq/jHsP0EoFkHUPzPpJS5BHE+RI0ZBBE8zASJeQUxPqR92QWRPMxkejkF8TzEapkGUT5p3Ehk0TxEX1kFED/GZE+5BrE+ZEQZRxE9BmQ8eUfRPsQ02USRfWZkLTlE8X3EHZlEMXxmZBX5RbF+JA5ZRhF/BuQKuUZxfof+gx1AgxsVP/hDfUMxXrgb6KJz3UMxfmfiYD2D8X7Fz9LAnYBRvIfMgP2HmTU/wAFdgLG9x7nCcb2Bcb6ntqIdgRG+Jc+qIn2B0bzHoMLdgzqRvoeagz2CMb0nkOUjnYNRv8eHw/2Dsb+eZ35gXcLxvCd4InC9wHH/p2uhHcDR/kXPYkF9wTH9x1XB3cJkgRQZ2JtPgj3Bkf8Gb0MCncCBA7vW+Vs05oL9wlH8RzBDXcMR/5ynIKO9wBH+ZxpicB4Dcf3nDeB+A9H8hg8EgN4EtbzeE7vXu9TlzvThngDyP4brgf4DOJI+JuIiXgGyP+bY5+K+AhI+htKDHgLSP50mySN+AnI/xr/Cc94Dkj9Gs0A+QVI95c6p4J5Csf+mo6D+QzvyPyaXIV5BEn3GjOXBvkCyf4aHgh5DMj+fBnsCfkHSfMZ0wnLeQjJ9JmUjPkBSfuXOXuOeQXJ9hlWD/kM7snwmTCBegpJ95kTl4L6C8nyGPIEehFQ7nAYwAX6BMr6mJqJx3oByvGYgYj6Bkr8FzhcCnoJSvaYNov6DOrK9JgEjXoNSf8H3M7qF8r2B8BrHErwh6zB6xDL+wdzaxJL8gdsxOshUOyHNmsTSvcHHMfrFUvxhvlrFsv8BszK6xnL+gacax3K8QaMzesYS/8GT2seS/mGLMDsH8v0BgJsG0v+hdzD7BFM/IWlbB9K9wWMxuwUTPqFeGwXTPiFTMnsGMzzBStsEsz2hRzM7BpM9ITubBvM+4TMz+wVzPYEoW0QTfCEjMLtEc33hGRtE031hDzF7R1M8AQXbRZN+oPsyO0UzfUDym0XzfwDrMvtGs32g41tHE30g1zO7RlN8oMgbh3N/QL8we4QzveC024STvICtkTuJl3yhm4fTfcCZ+4WZU7xgkluGE74giruFmnO8wIMbh7M8QHd7hZmzvuBr24eTvYBgO8WbM79AWJvEU/7ATPvFmtO+QEFbxRP9wDW7xZlz/4AuG8XT/wAie8cj874b/oNQKzvG8/zAHzObx1P/YBP7x7P+AAlwWAQQPoPufLwAfHQ+sLw8Bs/VfXwAfrX6w+viB8EwPAOz/6/+Z63wHdrbqb6cAZA+gc+KfvwCsD4Dff9cAznwPQNk/7wDcD5DUOY8HEPQP4M/fHxDED+cwyy83EAwfgMZ/nE8QPB9gw19nEJQPsPO+r38QVB8Auv+5O/+5hB9QtU+vEJwf5xCvD8cQtB/QqM/s3xAkGJAa7xCqP7CTpa/3EMwfAMZS/B/gc53fJyAULzCZLz8gzmwf8JLvVyAsL9CPOc9vIFwvkImPhyB0L+fghN+fIIwvMIAvmLcgJBdGVQ99ziGkL1+ZeOYh1C8fcv4irX7fmWsWMewvn2UuMQQ/f5liRjEcP89dXjFMPx+ZWXYyZa7fUo4xfD8vmU6mMZQ/70e+MTQ/P5lD1jGsPx9A7jN2bW+ZOwZB9D+/Nh5BDE/vmS42QSRPPypOQTxPj5klZkFUT28ifkHEPy+ZHJZBbE/vFa5BhE8/mRHGQZxP/wreQcxPv5kE9kHkHw8ADlG0T1/r+14nUB6tfh/1Hsw/UW1P8G5XUCxfL+o5Lm9QXF+f6J6HUERYzu8Uz+DOn1B0Xz/fOT63UERf/9j+z1CkX+dP1E7nUNRfn8+eHP9Q7F/vyu4XYLxX3mXnz8fOL2C8X6/ErpxHYDRvb75uX2BMb99zvN53YBxvD7UOj2DOBG9fsF6nYJRvH6o5Hr9hZa5Pok7XYIxf5y+fLu9grG/vmO6cB3DEb6+Srh9wDH9vc4xuN3Akf9+K3k9wzjx/n4SeZ3B8b15+zH5x9G+ueZZxhH/+dMyucZx/3nHGcbR/DmrM3nFUf85j9nHkf65gzA6BzH/+WyaBFI9OV8w+gfx/LlRWgSyPzkrMboFcj65HhoF0j45EzJ6BjI9OPraBRI8OOMzOgaSPXjPmgWx/ri7M/oG8j24oFpHUj94mzC6RHJ8OH0aRNJ9+HcxekQSfXhp2kUyfrhWYjpF8mO8U/hCmkXyfvpkKvpGUn34E1pGsn165Ae6R3J+u/K0HoB3WBZ/2bR+gHTWf7Q0cN6AMr37rfU+gPKjvFOc+5T1noDyvjuCNnH+gJK/e292XoISvvnPYva+gbK9+0n3HoHKcr15eMsyvHskd96HOrQ5uxG0PsLSvvr85vSew/K9+uX0/sBS/5z6zPVewRL+Oro2cb7Bcv76mvYewLL8Oc6INn7B0v16dXbewzoy/jpWNz7Ckv96QOd3nsNS/noqd/7Dsv0dehF0XwLy/X5J+HM8zbXlGwTTPLXNewUzPM31udsFkzz1ojsF8z5MdZabCNc9gvsEEz00xXdbBrMjvFA1X7sGszzPNUAbR9M89Tx7RxM8z/Ug20QzfTURO0TzfmZ1l0lTf7Tp+0dzPzZk3ltFs3x0zrtKtzy7MxtG0370p3tEk3w0lzPbRhN/NHg7hzN+tG8wm4eTfbRU+4RTvnQ3MVuFE7+0IbuFc760CXIbhdO9t/Gyf4BzN33P3vLfgpO8N8wzP4By86O8UPes85+C8724TztTvTeBMF/Ds753bOZwv8AT/XdVcR/Ac/9fN08xf8Bw1Do3NcYx38GT47xTdyNyP8M5M/y3ELKfwZP99vzl8v/CU/826zNfwrP/njbSM7/DE/22xbJwHAPT/LassHwAMD11zo1w3ADT/HZ0cTwHOrQ7dltxnAFQPvZM5vH8AbA+dkJyXAIQP512KXK8AnA89hzycxwA8D/2A/N8AzA8smXn2Adz/fHQOEbQPPBluJhEUH4xpPhEsF74lM0xjVhEsH3xbbhFcHzNcWIYRdB+sU54RjB8z3Eu2EaQfLEfOEbwfk+xA5hHUHzz+Enz/jJk3FiHsH2w0LiEcL0yZMUYhNC98KV4hTC9cYSZ2IWQvviPkD/wcpiE2fC9MGL4hHEB+VcYWmRXWIZQvzAvuIawvrJkIBjHcL2wCHjH0Lyxr/Cs3MBtlL/RbTzA4PD9OP4BT/Or7fzBsP+dM5kuXMIQ/LOMrnK8wnD/s3OvHMLQ/PHPYO98wzD+M04v3MM7kP0zNSw9A/D+cyHWbJ0AbxS58xXs/QJwUSM+UrL2rV0BET/xzuPtvQFxPLLErh0CdG1V+DK4Ln0B0T8xzp8u3QBRPjKGLz0DOpE9snmvnQIxPvJk5u/9AvE8MlQsXUARf51yQWy9QHF88jTuYR1AsSJ8lhvtfUDRfvDOAu3dQZF8LfI5R1E8zW3emUXxfG3G+Uu1eM2ts1lHEXytm7lHcXzN7YQZh9F87Wx5hDG8zi1Y2YSRv21FOYSxPM5tLZmE8b8tDfmFsbzM7QpZhhG/7O65hnG8zSzfGYbRvKzTeYZRfM+st9mHMb1ssDnHkbzOLJCZx/G/bHz5xFH8zKxtWcexP6xRucSx/MzsQhnF0f4sLnnGMf3MrArZxTF8L/wrPcM0adX/3Oudw1H+r9Tmq/3Dsf/vw+heABI/HK+kqL4AciMd15gqcR4AcjzveOl+ATI8bc9sad4HFnrvRuo+AmGSPjo7Hdc0Kv4Csj8tzxsrXgMSPG8Ia74HmxV+9ageQ3I+7uLqcH5AMn3uyejeQ9I8766w6T5AaTV7botqcZ5Akn7ufun+QPJ9bc5Zal5CEn6uRqq+Qzpyf+4z6x5Bsn0uIOUrfkLSfm4Oa95DknzPqfg6h/J/KeyahFK8z+nM+oSyvSm9WocyfM5pqbqFErwpphqFcr6M6YZ6hdK+vAlykr7qZVM6hjK9aS+ahvK8aqUX+oi2vQRaxGu2+upk7LrEEv3o1RrHUrzqZL16xVJ9qJ3axZL+6mSKOsTS/Ch6msUy/qpkUvrGUvxoT1rIlntqZDO6xfL+6CQbB3L96uQMewcS/Ov05N8AZxqWv+IlPwDzIL5RK8jlJZ8BUzyrvKX/APM/Xeup5l8AZxS7K5TnJr8CEz4rficfAtM/Mxs/IpNe598Dkz5rUOZkP0PzPWs5ZJ9AU3+eKxok/0Czf2sHZ5FfQbM8KBsJE31q1WZyH0FzfGq8Zn9FVz6c5SbfQdN8qpCnP0Lzf5+qd6efQ1N+ql6mc/9Ck3xqWGRfhTV5Kc45JL+Ds3yqLKUfgrjTvCogJX+AZ3f7KM4HJd+BM7xl9juIlnjNpeKbhfO9Jdb7hrO8zCW/W4cTv6Wvu4dzvMzlnBvH074liHvGU7zPZXTbxHO+5Wk7xDP8z6VJm8VT/OU5+8Wz/M2lGlvGE/7lBrvGc/zPpOcbxJP+pM97xnM8ziTD28cz/KScOATz/M+kgJgG0/zkcPgH8/zPZElYB5P8pDm4BRA8zWQaGASwPOQOeAYwP12n7aLcAGCWeSfg5SM8AvA8J8gjnANQIOM/l5wROXVntWBcQ7A/nqeioLxDUD/nj+JxHEBwfKdwoXxA0Hwnj2Qh3EAQYH0RZ1FicjxBkH6nPqKcQBB/5c8r4vxBMH0nGSNcQzpQfmcGY7xDEH8m5OcgHIKwf+bH4HyAML+fZrtg3INwfuau4nE8gPC95pXhnIPQfWXOiWH8gbC+JmoiXIM5UL0mUSK8gnC8JjjkIxyC0L1mJWN8gzC9nGYMY9yElnrh5DjFmJC94cyYx/C/Ibj4xZiw/GGpWMhVOSGJuMWZEPyhfhjF0P3hanjFmXD/IVbYxjD8YUc4yZiWeSEnmMdQ/CEP+MWbsP8g8FkEUP4g2LkFmHE9IMEZBBE8IKl5BZkxPWCV2QaQ/iB2OQWY0T0gXpkF8T5gSvkFmrE84CdZBZE8YBu5CrjUe2P/XB1AXlU/+NUcfUBeNP/Z3N1AkX8dY81dPUDxY75So7jmnZ1A8X4jrh39QDFjmZzXlR5dQVF943Xecr1CcXzjXN8dQtF/4c9D331DMX7jKt/dQzgxfCMYHD2BsX+jCOecnYBRvGLsXP2FtX3O5h1dg5F+4sbdvYM5cb5iul4dg/F94qzl3n2BEb+ip57dgpG/nOKU3z2C8b2idZ5znYIxvuJi3/2B0bwhzlAcXcNRvyI3HL3DOHH84jDdHcDR/aISZZ19wTH8nfnZxZH9XmXaOcXx/N3OmcZR/15lpvnEEf7dm1nGEX3eZYO5x7G83WgaBrH+HmVUegcR/R082gfR/B5lJToEMjzdBZoFUj6fMfYI8j0c2loFsj7c0zK6BnI/nLMaBJI+nJszegbSPZyD2geSPJxrMDpH8j1cSJpEUnxcMZD6SrX8FVpHcfycBbpGuRJ9X+VaHkBZtj/Rxpp+QjJjvlPfv9reQzoyf1+zWz5CknyfouSbnkLyfl+aW/5AWzg0uV+BWF6Dsn6fbOaYvoByv99b2R6DUn+e30LZfoASvd8p2nHegTK9Xx1aPoDSvN3PENqegfK9nvGa/oM6Ur9e61tegZK8ntjkm76Csr3exdgew3K+Hx6zGH7DErx61rh2Hc6aGT7Akv/ek9mewzlS/J50mf7A8v5ebOZaXsGy/x5PGr7Ccv2cXjxbHsVW/i/bfsM7Mv7eFtvewhL92f8wOweS/xnomwfy/hnTMPsEUz7ZsVsEsz5ZpzG7BRM/GYYbBXM+mXsyewXTPZli2wYzP1lbMzsGkz7ZT5sG8z+ZLKP7B1M/XEkgE32Yt0hzfZC7f+MQyXtFM33Y0dtGGZN8WK47Sfd+P32EiRpkjvtHsz7Yh1tGs35YxHu7RxNh/ZDYVBuH0rzMWEh7iDS5GCjbhJO9zJgdO4Qzvxv3FZ+CdFQ0uFvkVf+E1HgbD6wWX4Gzvlu+YxOGlHMfgtO/23PXf4ITof2TnltOV9+Dk73bQdZwP8PzvNso1J/AU/2ZzwmU/8MzvJrwlV/DORP9WtFVv8ITvNrE5NYfwdP+2pLWf8Iz/nJ71rh02mDXP8Lz/pnOWpefwpP9GjUX/8M7U/5aIlRcABA9WgrlVLwAcBxrIGT8AqWc/pX1GAez/9XheAcYcDyVxdgFkCH9ktXLMjgFkD1VppgGUDzVmzL4BTA8VY9YCNR4FbszuAawP5WoGEXwPhWHMHhH0D0VbNhEkH3VTzE4RDB+lS2YRPB9lRcx+EWwf1UOWEYQftUAMrhHcD5U9xhG0H8YfYCMzxTX2EZwfNTQOIfwfQ0UpJiEULyYvABQfViFm5B9VHm4hXC+FFoYhZkQv1RGeIYwvBQq2IWakL+UGziF0LzUC5iGuLP/V+NT/IBR9D/UxtBcwBDj/Be3kLzAcP+c16TRHMDQ/9eL0Ol8wFCVetdy0dzAEP+fV39SPMGQ/5dTkcKcwlD+mNc7tFc0U1zGYxT/XNGY+w7QHQPQ/5VO75B9A3D+loPG1JE/nRaxET0A8TyWpJJxnQAxPVaFUf0BUTzVznjSXQGxPFZsUr0HGTQ+X9MdAtEh/ZEWTOUTfQIRPBY0E90DkT+dViFQPUPxPNYU0nCdQfD+FgIQ/UBRftGF4VlFEX1ZVdm00bIZRZlxf9GWeUbRPlFy2UWaMX8RUzlF0XxRQ5lJmZd5ESP5R7F8kRRZhZgRvVD0uYbxfxDtGYWY0bzQ6XmFMb4Q1dmFmZG9kMo5hfG+UKqZhZpRv5CW+YaxvFB7WYmZdniQT7mEcb1QLBnHm9G+kBh5xxG9E/UM6N3ATZd4E9wNPcDx/16Tto2dwE8Vv7BOcf3HN7tTl05dwVH9Ew+RDr3CEf65/cKN03Dlz33Ccf8TXw/dwzHjO7+TUzNMPgOR/RMs5QyeAFI9UwFM/gCyPzD6FZm64g2+AXI/UsznTh4B0j7Sws5+ARI/nBKwDt4Ckj5StkxzPgLyPhJ+D54CMj+aP5rBUlJMXkASfVI5TnC+Q1I/0hPNHkDSfs2F+XpFMn16dPgUTb46SZs3uM3KmkWSfY2q+kWaUn7Nl1pHEn+Nd7pFm3J8TVgaize6jVx6hZgyvQ042oSSvI0tOoWasn8NBZqE8rzNAfqFmbK9DNZahhK+TMK6hZpyv4yvGoVSvMyfeoQC0pwA</item>

... 剪断
        <item name="Gain6">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</item>
    </list>
</obj>

最佳答案

这就是我到目前为止所拥有的。
根据可读数据推断,您使用的文档并非来自实际的 PCR 运行。这是一个颜色补偿运行 ( short overview that seems to match the file ) ( full updated manual, page 250, not as fitting )。具体来说,它似乎是“FAM/Pulsar 650”染料的颜色补偿运行。
正如您所指出的,输出类型是具有 2400 个“计数”的“采集表”,我相信它必须与您通常从 PCR 运行中获得的输出不同。我相信您已经找到了这些,但是一些公开的 PCR 模板示例(未完成的运行)是 here , here , herehere .

根据您文件中的 LCRunProgram,这里的协议(protocol)是:
以 20°C/s 的速度保持 95°C 0"
保持 40°C 30",20°C/s
以 0.1°C/s 的速度保持 95°C 0",采集模式“2”。

因此,我们预计采集时间范围持续估计 (95°C-40°C)/0.1°C/s = 550 秒,大约;在此期间,每秒应该有固定数量的采集事件。

EDIT 0 - 这是我在开始时所做的,所以我没有删除它,但后来我得到了更多有趣的信息(见下文)。

我用一个简单的 Python 脚本(我是 Python 专家)查看了数据,以搜索模式。该脚本将数据的初始字符串保存在名为 values 的字典中。在这里发布太长了;所以here's it in a gist ,就像你必须做的那样。

#!/usr/bin/env python3

import base64
from collections import OrderedDict, defaultdict
from values import values

def splitme(name, sep):
    splitted = base64.b64decode(values[name]+'==').split(sep)
    print("{:<12} [{}; {}] separated in {} chunks: {}".format(
            name,
            len(values[name]), len(base64.b64decode(values[name]+'==')),
            len(splitted),
            [len(i) for i in splitted]))
    return splitted

if __name__ == '__main__':
    allchunks = defaultdict(list)
    separator = b'\r'
    print("separating by:", separator)
    for key in values:
        data = splitme(key, sep=separator)
        for i, item in enumerate(data):
            allchunks[item].append((key, i))
    print("Common chunks:")
    for location in [value for item, value in allchunks.items() if len(value)>1]:
        print(location)

让我们避开显而易见的事情,说 ProgramNoCycleNo持有相同的数据;和所有 Gain是相同的。所以我只发一张。

现在尝试使用分隔符 b'\r' 的脚本(只是尝试一个)将其中的一些切成 272(271+个分隔符)字节的块。其他的不整洁。
separating by: b'\r'
SampleNo     [1536; 1152] separated in 5 chunks: [174, 271, 271, 271, 161]
ProgramNo    [1531; 1148] separated in 6 chunks: [47, 271, 271, 271, 271, 12]
SegmentNo    [1531; 1148] separated in 5 chunks: [169, 271, 271, 271, 162]

通过 b'\t' 分隔给出类似的结果:
separating by: b'\t'
SampleNo     [1536; 1152] separated in 5 chunks: [204, 271, 271, 271, 131]
ProgramNo    [1531; 1148] separated in 5 chunks: [76, 271, 271, 271, 255]
SegmentNo    [1531; 1148] separated in 5 chunks: [199, 271, 271, 271, 132]

并由 b'\n' 分隔以类似的方式分割这次的 yield :
separating by: b'\n'
Gain1        [3046; 2284] separated in 10 chunks: [81, 271, 271, 271, 271, 271, 271, 271, 271, 26]  

所以我并不是在暗示这些“分隔符”有任何重要性;我认为它们是罕见的字符,它们似乎将数据切成 272 字节的块,而这个 272 字节的值对于理解这些数据的存储方式可能很重要。

每个字符串“BARZ”的开头似乎是一个“foo-bar”的东西;可能在标题的开头设置为检查。

另一件有趣的事情是 gains数据分成 8 个相同大小的块(加上其他两个较小的块)。如果此数据来自 96 孔板,我将开始探索这是否可能是一个标题,然后是 8 个可拆分为 12 个项目(列)的块(行),以便 8*12=96 复制设置96 孔板。

此外,如果这个“每行 272 字节”假设成立,那么 ProgramNo 中的数据, SampleNo如果板未装满,则可以解释确实分成 272 字节块的等,并且一些孔有 sample (有几条完整的线)而其他孔是空的。我不确定这对于色彩补偿板是否有意义。
Time , Temperature , ErrorFluor s 不分成块,您认为它们是一组连续值是正确的;虽然不一定 float 。荧光可以被捕获为可能是正整数的“单位”(我没有 LightCycler 所以我不知道是否是这种情况)。

这就是我目前所处的位置。我不确定我是否有时间走得更远。如果我没有回复,祝你的努力好运。

编辑 1:

所以关于SampleNo数据,它似乎是这样构造的:
1) 一个 header ,可能会或可能不会被 0x00 分隔,例如:
* BARZ header ,然后是 2 次 0x00(共 6 个字节)
* 三个字节,然后是 0x00(共 4 个字节)
* 17 个字节,然后是 0x00(共 18 个字节)
2) 一系列数据,每个数据由 16 个字节组成并以 0x00 终止(因此每个数据为 17 个字节)。
这意味着 Samples包含一个头部,加上 66 组 17 字节。

编辑2:

使用这段糟​​糕的代码将所有内容按 0x00 拆分:
def splitme(name):
    data = base64.b64decode(values[name]+'==')
    hit = 0
    index = 0
    countit = 0
    splits = []
    while hit >= 0 and countit < 500:
        countit += 1
        hit = data[index+1:].find(0)
        index += hit+1
        if hit >= 0:
            splits.append(index)
    lastindex = -1
    splitted = []
    if splits:
        for index in splits:
            splitted.append(data[lastindex+1:index])
            lastindex = index
    else:
        splitted = [data]

产量:
separating by: 0x0
SampleNo     [1536; 1152] separated in 70 chunks: [4, 0, 3, 17, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16]
ProgramNo    [1531; 1148] separated in 71 chunks: [4, 0, 3, 2, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 12]
SegmentNo    [1531; 1148] separated in 69 chunks: [4, 0, 3, 18, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16]
CycleNo      [1531; 1148] separated in 71 chunks: [4, 0, 3, 2, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 12]
Time         [11944; 8958] separated in 63 chunks: [4, 0, 3, 45, 14, 42, 76, 46, 172, 110, 109, 15, 81, 90, 111, 108, 78, 46, 175, 141, 88, 209, 74, 117, 156, 170, 59, 107, 78, 103, 125, 171, 103, 170, 191, 333, 154, 187, 11, 257, 149, 208, 173, 156, 153, 412, 72, 55, 207, 131, 131, 274, 284, 238, 19, 241, 247, 13, 74, 558, 763, 8, 0]
Temperature  [6731; 5048] separated in 14 chunks: [4, 0, 3, 394, 186, 543, 177, 173, 530, 534, 371, 714, 373, 1032]
Error        [398; 298] separated in 21 chunks: [4, 0, 3, 2, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 12]
Fluor1       [7539; 5654] separated in 38 chunks: [4, 0, 3, 31, 13, 7, 7, 426, 331, 218, 187, 11, 10, 13, 7, 6, 7, 48, 45, 217, 840, 6, 7, 14, 7, 6, 7, 7, 6, 1178, 8, 6, 1147, 7, 6, 141, 630, 2]
...
Gain1        [3046; 2284] separated in 145 chunks: [4, 0, 3, 9, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 16, 8, 7, 16, 16, 16, 16]
...

所以SampleNo , ProgramNo , SegmentNo , ErrorGain s 全部拆分为 17 个字节的块(16 个字节 + 0x00)。

编辑 3:ProgramNo 的前十五个 17 位块(以及副本 CycleNo )和 Error是相同的。
只是为了澄清,我描述的“块”是您所描述的一系列数字对,其中一个增加了 0x12。您提到的 0x00 是块之间的分隔符。

编辑 4:
关于 Gain数据,我最初的“272 字节”块和 (16+0x00) 字节块之间的链接,是有 16 个块的重复模式,其中 15 个是“16+0x00”块,最后一个块有 0x00在中间。所以 17 字节(=16+0x00)* 16 个块 = 272 字节的总重复。
整个字符串的构建如下:“标题”部分,然后是 8 个 17bytes*16 块的重复,最后是 4 个 17bytes 块。因此,一方面我对 8 个块是正确的,但显然我在与 8x12 孔 PCR 板平行时错了。这里更像是 8*16 (+4)。
关于 Fluor等数据,我没有答案,但我会尝试剥离标题,看看是否有任何(整数或浮点数)压缩算法可以处理它......压缩数据将解释为什么这些字段的长度不同.

关于java - 专有 XML 文件(Roche LC480 .ixo 文件)中的二进制字段编码/序列化格式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40160627/

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