这是一个与 this question 相当相似的问题。但有一个关键区别:我不是根据索引而是根据某些标准来选择要更改的数据。
如果我应用的条件返回单行,我希望能够以简单的方式设置该行中某一列的值,但我的第一次尝试不起作用:
>>> d = pd.DataFrame({'year':[2008,2008,2008,2008,2009,2009,2009,2009],
... 'flavour':['strawberry','strawberry','banana','banana',
... 'strawberry','strawberry','banana','banana'],
... 'day':['sat','sun','sat','sun','sat','sun','sat','sun'],
... 'sales':[10,12,22,23,11,13,23,24]})
>>> d
day flavour sales year
0 sat strawberry 10 2008
1 sun strawberry 12 2008
2 sat banana 22 2008
3 sun banana 23 2008
4 sat strawberry 11 2009
5 sun strawberry 13 2009
6 sat banana 23 2009
7 sun banana 24 2009
>>> d[d.sales==24]
day flavour sales year
7 sun banana 24 2009
>>> d[d.sales==24].sales = 100
>>> d
day flavour sales year
0 sat strawberry 10 2008
1 sun strawberry 12 2008
2 sat banana 22 2008
3 sun banana 23 2008
4 sat strawberry 11 2009
5 sun strawberry 13 2009
6 sat banana 23 2009
7 sun banana 24 2009
因此,与其将 2009 年周日的香蕉销量设置为 100,不如什么都没有发生!最好的方法是什么?理想情况下,解决方案应该使用行号,因为您通常不会提前知道!
最佳答案
有很多方法可以做到这一点
1
In [7]: d.sales[d.sales==24] = 100
In [8]: d
Out[8]:
day flavour sales year
0 sat strawberry 10 2008
1 sun strawberry 12 2008
2 sat banana 22 2008
3 sun banana 23 2008
4 sat strawberry 11 2009
5 sun strawberry 13 2009
6 sat banana 23 2009
7 sun banana 100 2009
2
In [26]: d.loc[d.sales == 12, 'sales'] = 99
In [27]: d
Out[27]:
day flavour sales year
0 sat strawberry 10 2008
1 sun strawberry 99 2008
2 sat banana 22 2008
3 sun banana 23 2008
4 sat strawberry 11 2009
5 sun strawberry 13 2009
6 sat banana 23 2009
7 sun banana 100 2009
3
In [28]: d.sales = d.sales.replace(23, 24)
In [29]: d
Out[29]:
day flavour sales year
0 sat strawberry 10 2008
1 sun strawberry 99 2008
2 sat banana 22 2008
3 sun banana 24 2008
4 sat strawberry 11 2009
5 sun strawberry 13 2009
6 sat banana 24 2009
7 sun banana 100 2009
关于python - 在不使用索引的情况下替换 pandas DataFrame 中选定单元格的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17729853/