scala - LiftWeb Loc.Template 参数

Question

我有模板和两个片段。我可以在模板中获取 ID 以选择动态片段吗？

def remote =
  Menu.param[Point]("Test1", "remote",
  id => inTransaction(Points.lookup(id)), _.id) / "point" / * / "remote" >>
  //inTransaction(Points.lookup(id)) match
  //  case point.Kind.remote =>
  Loc.Template(() => Templates("point" :: "remote" :: Nil).openOr(Nil)) >> Hidden
  //  case point.Kind.otherremote =>
  //Loc.Template(() => Templates("point" :: "otherremote" :: Nil).openOr(Nil)) >> Hidden

Answer 1

您应该使用ValueTemplate，它提供当前解析的值作为参数。

下面的代码未经测试，但您应该明白:

def remote = Menu.param[Point]("Test1", "remote",
  id => inTransaction(Points.lookup(id)), _.id) / "point" / * / "remote" >>
  Loc.ValueTemplate(point => point match
    case Full(p) if p.Kind.remote => Templates("point" :: "remote" :: Nil).openOr(Nil))
    case Full(p) if p.Kind.otherremote => Templates("point" :: "otherremote" :: Nil).openOr(Nil))
    case _ => NodeSeq.Empty
  ) >> Hidden