我现在正在开发 SIP 数据的适配程序。不幸的是，数据位于具有以下结构的 csv 表中:
f; Abs(Zm); Std(Abs); Phi(Zm); Std(Phi); Re(Zm); Im(Zm); Time [s]
1.0000000e-001; 7712.6262; 0.0247; -0.003774; 0.000001; 7712.5713; -29.1074; 3418623040
2.0000000e-001; 7712.4351; 0.0030; -0.007543; 0.000001; 7712.2157; -58.1732; 3418623056
5.0000000e-001; 7710.8455; 0.0094; -0.018837; 0.000002; 7709.4775; -145.2434; 3418623063
1.0000000e+000; 7705.3763; 0.0098; -0.037637; 0.000000; 7699.9195; -289.9395; 3418623067
2.0000000e+000; 7683.8120; 0.0241; -0.075058; 0.000001; 7662.1778; -576.1935; 3418623069
5.0000000e+000; 7539.7945; 0.0080; -0.184724; 0.000002; 7411.5201; -1384.8720; 3418623071
1.0000000e+001; 7088.6894; 0.0060; -0.351521; 0.000001; 6655.2169; -2440.8206; 3418623072
f; Abs(Z12); Phi(Z12); Abs(Z34); Phi(Z34); Abs(Z14); Phi(Z14); Time [s]
1.0000000e-001; 1.7821; 3.139014; 0.2545; -3.141592; 7710.5896; -0.003774; 3418623040
2.0000000e-001; 1.7850; 3.133381; 0.2572; -3.126220; 7710.3930; -0.007543; 3418623056
5.0000000e-001; 1.7755; 3.121223; 0.2514; -3.133763; 7708.8186; -0.018838; 3418623063
1.0000000e+000; 1.7683; 3.100815; 0.2503; 3.139466; 7703.3580; -0.037638; 3418623067
2.0000000e+000; 1.8091; 3.058834; 0.2538; -3.123705; 7681.7502; -0.075060; 3418623069
5.0000000e+000; 1.5547; 2.943611; 0.2398; -3.136317; 7538.0045; -0.184727; 3418623071
我正在使用 numpy.loadtxt() 例程从表中收集数据，如下所示:
def load_datafile(filename):
try:
x_data, y_data = numpy.loadtxt(filename , unpack=True, usecols=(0,1),)
except IOError:
print('There was an error opening the file: {0}'.format(filename))
x_data=[]
y_data=[]
return x_data, y_data
我知道在 loadtxt() 命令中使用表中的特定 block 没有进一步的标识符。但是有一个方便的解决方法吗？
否则是否有一个简单的脚本可以将 csv 输入文件重新排列为单 block 列？
提前致谢! 问候， 贡纳尔
最佳答案
您可以首先将输入数据拆分为 block ，然后使用 loadtxt 或 genfromtxt (我更喜欢这个，因为它有一个读取 header 的选项)。
from numpy import genfromtxt
from StringIO import StringIO
def read_by_block(filename):
blocks = []
data = open(filename).read()
for blk in data.split('\n\n'): # we assume that blocks are separated by two newlines
blocks.append(genfromtxt(StringIO(blk), delimiter=';', names=True))
return blocks
data = read_by_block('data.txt')
print data[0].dtype.names # print fields for first block
print data[0]['StdPhi'] # print column 'Std(Phi)' in 1st block
关于 python : How to load column from multiblock csv tables?，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/10426908/