我在用 Python 格式化一些代码时遇到困难: 我的代码在这里:
keys = ['(Lag)=(\d+\.?\d*)','\t','(Autocorrelation Index): (\d+\.?\d*)', '(Autocorrelation Index): (\d+\.?\d*)', '(Semivariance): (\d+\.?\d*)']
import re
string1 = ''.join(open("dummy.txt").readlines())
found = []
for key in keys:
found.extend(re.findall(key, string1))
for result in found:
print '%s = %s' % (result[0],result[1])
raw_input()
到目前为止,我得到了这个输出:
Lag = 1
Lag = 2
Lag = 3
Autocorrelation Index = #value
......
......
Semivariance = #value
但是我想要的输出是:
Lag AutoCorrelation Index AutoCorrelation Index Semivariance
1 #value #value #value
2 #value #value #value
3 #value #value #value
如果此输出可以在 CSV 中实现文件或 txt 文件,那就太好了!
我认为这是输出循环的一种方式,但我不太擅长循环。
我更新的代码(旧版本)
基于@mutzmatron 的回答
keys = ['(Lag)=(\d+\.?\d*)',
'(Autocorrelation Index): (\d+\.?\d*)',
'(Semivariance): (\d+\.?\d*)']
import re
string1 = open("dummy.txt").readlines().join()
found = []
for key in keys:
found.extend(re.findall(key, string1))
raw_input()
for result in found:
print '%s = %s' % (result[0], result[1])
raw_input()
尚未编译!我正在使用 IDLE python 2.6 ,不知道错误消息,因为我不知道提示中的暂停命令!
原始问题
我对 python 完全陌生,有一个问题。我正在尝试处理一个大文本文件。 这里只是其中的一个片段:
Band: WDRVI20((0.2*b4-b3)/((0.2*b4)+b3))
Basic Statistics:
Min: -0.963805
Max: 0.658219
Mean: 0.094306
Standard Deviation: 0.131797
Spatial Statistics, ***Lag=1***:
Total Number of Observations (Pixels): 769995
Number of Neighboring Pairs: 1538146
Moran's I:
***Autocorrelation Index: 0.8482564597***
Expected Value, if band is uncorrelated: -0.000001
Standard Deviation of Expected Value (Normalized): 0.000806
Standard Deviation of Expected Value (Randomized): 0.000806
Z Significance Test (Normalized): 1052.029088
Z Significance Test (Randomized): 1052.034915
Geary's C:
***Autocorrelation Index: 0.1517324729***
Expected Value, if band is uncorrelated: 1.000000
Standard Deviation of Expected Value (Normalized): 0.000807
Standard Deviation of Expected Value (Randomized): 0.000809
Z Significance Test (Normalized): 1051.414163
Z Significance Test (Randomized): 1048.752451
***Semivariance: 0.0026356529***
Spatial Statistics, Lag=2:
Total Number of Observations (Pixels): 769995
Number of Neighboring Pairs: 3068924
Moran's I:
Autocorrelation Index: 0.6230691635
Expected Value, if band is uncorrelated: -0.000001
Standard Deviation of Expected Value (Normalized): 0.000571
Standard Deviation of Expected Value (Randomized): 0.000571
Z Significance Test (Normalized): 1091.521976
Z Significance Test (Randomized): 1091.528022
Geary's C:
Autocorrelation Index: 0.3769372504
Expected Value, if band is uncorrelated: 1.000000
Standard Deviation of Expected Value (Normalized): 0.000574
Standard Deviation of Expected Value (Randomized): 0.000587
Z Significance Test (Normalized): 1085.700399
Z Significance Test (Randomized): 1061.931158
Semivariance: 0.0065475488
我需要提取星号***值之间的信息(例如:自相关指数
、半方差
值)并处理它,也许将其写入不同的文本文件或 Excel 文件。我可以这样做吗?非常感谢您的帮助。
最佳答案
为了按部分格式化数据,最简单的方法可能是按如下方式处理分段
keys =['(Lag)=(\d+\.?\d*)',
'(Autocorrelation Index): (\d+\.?\d*)',
'(Semivariance): (\d+\.?\d*)']
import re
string1 = ''.join(open("dummy.txt").readlines())
sections = string1.split('Spatial Statistics')
output = []
heads = []
for isec, sec in enumerate(sections):
found = []
output.append([])
for key in keys:
found.extend(re.findall(key, sec))
for result in found:
print '%s = %s' % (result[0],result[1])
output[-1].append(result[1])
if len(found) > 0 & len(heads) == 0:
heads = [result[0] for result in found]
fout = open('output.csv', 'w')
wrt = csv.writer(fout)
wrt.writerow(heads)
wrt.writerows(outputs)
fout.close()
关于python - 如何在 Python 中格式化输出?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11743257/