有没有办法使用 for 循环来执行下面的代码,而不是重复键入?
bar1 = [[UIView alloc] init];
bar1.backgroundColor = [UIColor blueColor];
[self addSubview:bar1];
bar2 = [[UIView alloc] init];
bar2.backgroundColor = [UIColor blueColor];
[self addSubview:bar2];
bar3 = [[UIView alloc] init];
bar3.backgroundColor = [UIColor blueColor];
[self addSubview:bar3];
bar4 = [[UIView alloc] init];
bar4.backgroundColor = [UIColor blueColor];
[self addSubview:bar4];
bar5 = [[UIView alloc] init];
bar5.backgroundColor = [UIColor blueColor];
[self addSubview:bar5];
最佳答案
您可以使用 C 数组:
enum { NBars = 5 };
@implementation MONClass
{
UIView * bar[NBars]; // << your ivar. could also use an NSMutableArray.
}
- (void)buildBars
{
for (int i = 0; i < NBars; ++i) {
bar[i] = [[UIView alloc] init];
bar[i].backgroundColor = [UIColor blueColor];
[self addSubview:bar[i]];
}
}
或者您可以使用NSArray
:
@interface MONClass ()
@property (nonatomic, copy) NSArray * bar;
@end
@implementation MONClass
- (void)buildBars
{
NSMutableArray * tmp = [NSMutableArray new];
enum { NBars = 5 };
for (int i = 0; i < NBars; ++i) {
UIView * view = [[UIView alloc] init];
view.backgroundColor = [UIColor blueColor];
[tmp addObject:view];
[self addSubview:view];
}
self.bar = tmp;
}
或者,如果您想保留这些单独的属性,您可以使用“字符串类型”并使用 KVC:
- (void)buildBars
{
enum { NBars = 5 };
// if property names can be composed
for (int i = 0; i < NBars; ++i) {
UIView * theNewView = ...;
[self setValue:theNewView forKey:[NSString stringWithFormat:@"bar%i", i]];
}
}
或
- (void)buildBars
// else property names
for (NSString * at in @[
// although it could use fewer characters,
// using selectors to try to prevent some errors
NSStringFromSelector(@selector(bar0)),
NSStringFromSelector(@selector(bar1)),
NSStringFromSelector(@selector(bar2)),
NSStringFromSelector(@selector(bar3)),
NSStringFromSelector(@selector(bar4))
]) {
UIView * theNewView = ...;
[self setValue:theNewView forKey:at];
}
}
但还有一些其他选择。希望这足以让您开始!
关于objective-c - 使用 for 循环为多个对象分配、初始化和设置属性?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13262028/