php - 如何对二维数组求和

Question

晚上好

我有一个问题。我有两个数组:$duration_c[$k][$s]。它打印一切正常

$duration_c[0][0]="19:30:00";
$duration_c[0][1]="00:10:00";

$duration_c[1][0]="00:30:00";
$duration_c[1][1]="00:20:00";

比求和

$times=$duration_c[$k][$s];
function sum_the_time($times) {

  $seconds = 0;
  foreach ($times as $time)
  {
    list($hour,$minute,$second) = explode(':', $time);
    $seconds += $hour*3600;
    $seconds += $minute*60;
    $seconds += $second;
 }
  $hours = floor($seconds/3600);
  $seconds -= $hours*3600;
  $minutes  = floor($seconds/60);
  $seconds -= $minutes*60;
  // return "{$hours}:{$minutes}:{$seconds}";
  return sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);
} 
echo sum_the_time($times);

如何对$duration_c[0][0]+$duration_c[0][1]和$duration_c[1][0]+$duration_c[1][1]求和，以及如何打印？ 出现错误为 foreach() 提供的参数无效

Answer 1

您仅向 sum_the_time 函数发送一个值，如 $times=$duration_c[$k][$s]; $times 只有一个值，您可以通过这样的写法打印并检查该函数将获得什么值

$times=$duration_c[$k][$s];
echo $times;

使用

$times=$duration_c[$k];

这样您就可以将数组发送到您的函数，并且 foreach 不会给您错误

$times=$duration_c[$k]; // contains array of times
function sum_the_time($times) {

  $seconds = 0;
  foreach ($times as $time)
  {
    list($hour,$minute,$second) = explode(':', $time);
    $seconds += $hour*3600;
    $seconds += $minute*60;
    $seconds += $second;
 }
  $hours = floor($seconds/3600);
  $seconds -= $hours*3600;
  $minutes  = floor($seconds/60);
  $seconds -= $minutes*60;
  // return "{$hours}:{$minutes}:{$seconds}";
  return sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);
} 
echo sum_the_time($times);