我认为我想要的是一个递归函数,但是请让我知道是否有其他方法可以实现我想要做的事情!我不确定我能否很好地解释这一点,所以如果您需要进一步说明,请告诉我。
我有一个函数 findSeed(),它接受一个 id 并返回一个包含有关“种子”信息的数组:
function findSeeds($id) {
global $wpdb;
$query = "SELECT * FROM seedTable WHERE id = " . $id;
$seed = $wpdb->get_row($query, ARRAY_A);
return $seed;
}
它返回以下数组:
Array
(
[id] => 9
[name] => Sign
[seed1] => 4
[seed2] => 3
)
其中种子 1 和种子 2 是创建它所需的种子的 ID。我正在寻找一个函数来创建一个多维数组,格式如下,其中数组的第一部分包含第一个“种子”,下一个包含第一个“种子”中包含的两个种子,下一个包含两个其中每个包含的种子,依此类推:
Array
(
[1] => Array
(
[0] => Stripey Wallpaper
)
[2] => Array
(
[0] => Green Block
[1] => Aqua Block
)
[3] => Array
(
[0] => Bricks
[1] => Grass
[2] => Bricks
[3] => Glass Pane
)
[4] => Array
(
[0] => Rock
[1] => Grass
[2] => Dirt
[3] => Rock
[4] => Rock
[5] => Grass
[6] => Rock
[7] => Lava
)
)
到目前为止,我正在使用一个(可怕的)函数来做这件事,如下所示,但“ map ”可以是 2 到 8 行之间的任何内容,而且我正在努力了解如何将其变成一个简洁的小函数适用于任何事情:
function makeMap($id) {
// First Row
$rowNum = 1;
$oneSeed = findSeeds($id);
$map[$rowNum][] = $oneSeed[name];
// Second Row
$rowNum = $rowNum + 1;
$twoSeed = findSeeds($oneSeed[seed1]);
$threeSeed = findSeeds($oneSeed[seed2]);
$map[$rowNum][] = $twoSeed[name];
$map[$rowNum][] = $threeSeed[name];
// Third Row
$rowNum = $rowNum + 1;
$fourSeed = findSeeds($twoSeed[seed1]);
$fiveSeed = findSeeds($twoSeed[seed2]);
$sixSeed = findSeeds($threeSeed[seed1]);
$sevenSeed = findSeeds($threeSeed[seed2]);
$map[$rowNum][] = $fourSeed[name];
$map[$rowNum][] = $fiveSeed[name];
$map[$rowNum][] = $sixSeed[name];
$map[$rowNum][] = $sevenSeed[name];
// Fourth Row
$rowNum = $rowNum + 1;
$eightSeed = findSeeds($fourSeed[seed1]);
$nineSeed = findSeeds($fourSeed[seed2]);
$tenSeed = findSeeds($fiveSeed[seed1]);
$elevenSeed = findSeeds($fiveSeed[seed2]);
$twelveSeed = findSeeds($sixSeed[seed1]);
$thirteenSeed = findSeeds($sixSeed[seed2]);
$fourteenSeed = findSeeds($sevenSeed[seed1]);
$fifteenSeed = findSeeds($sevenSeed[seed2]);
$map[$rowNum][] = $eightSeed[name];
$map[$rowNum][] = $nineSeed[name];
$map[$rowNum][] = $tenSeed[name];
$map[$rowNum][] = $elevenSeed[name];
$map[$rowNum][] = $twelveSeed[name];
$map[$rowNum][] = $thirteenSeed[name];
$map[$rowNum][] = $fourteenSeed[name];
$map[$rowNum][] = $fifteenSeed[name];
return $map;
}
当所有“行”节点都为空时,它应该停止,因此以下只需要返回前两“行”:
Array
(
[1] => Array
(
[0] => Wood Block
)
[2] => Array
(
[0] => Dirt
[1] => Lava
)
[3] => Array
(
[0] =>
[1] =>
[2] =>
[3] =>
)
[4] => Array
(
[0] =>
[1] =>
[2] =>
[3] =>
[4] =>
[5] =>
[6] =>
[7] =>
)
)
任何提示、提示或解决方案将不胜感激,
谢谢。
编辑:快速说明为什么我希望采用上述格式 - 然后我将结果打印在表格中,第一个种子跨越整行,然后将其与下面的子项一起分解,例如所以:
$map = makeMap($_POST['theItem']);
$colspan = count(end(array_values($map)));
echo '<h3>' . $map[row1][0] . '</h3><br/>';
echo '<table>';
foreach ($map as $row) {
echo '<tr>';
foreach ( $row as $cell) {
echo '<td colspan="'. $colspan .'"><div class="seed">' . $cell . '</div></td>';
}
$colspan = $colspan / 2;
echo '</tr>';
}
echo '</table>';
最佳答案
<?php
$array = array('one', 'two', 'three');
for($i =1; $i<= count($array); $i++){
for($j=0; $j<$i; $j++){
$arrymulti[$i][$j]= $array[$j];
}
}
echo '<pre>';
print_r($arrymulti);
?>
输出:
Array
(
[1] => Array
(
[0] => one
)
[2] => Array
(
[0] => one
[1] => two
)
[3] => Array
(
[0] => one
[1] => two
[2] => three
)
)
关于php - 构建递归函数来创建多维数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14672540/