php删除数组中重复的单词

Question

抱歉，英语不是我的母语，也许问题标题不太好。我想做这样的事情。

$str = array("Lincoln Crown","Crown Court","go holiday","house fire","John Hinton","Hinton Jailed");

这里是一个数组，“Lincoln Crown”包含“Lincoln”和“Crown”，因此删除下一个包含这2个单词的单词，并且“Crown Court(contain Crown)”已被删除。

在另一种情况下。 “John Hinton”包含“John”和“Hinton”，因此“Hinton Jailed(包含 Hinton)”已被删除。最终的输出应该是这样的:

$output = array("Lincoln Crown","go holiday","house fire","John Hinton");

由于我的php技术不好，不能简单地使用array_unique() array_diff()，所以提出问题寻求帮助，谢谢。

Answer 1

我认为这可能有用:P

function cool_function($strs){
    // Black list
    $toExclude = array();

    foreach($strs as $s){
        // If it's not on blacklist, then search for it
        if(!in_array($s, $toExclude)){
            // Explode into blocks
            foreach(explode(" ",$s) as $block){
                // Search the block on array
                $found = preg_grep("/" . preg_quote($block) . "/", $strs);
                foreach($found as $k => $f){
                    if($f != $s){
                        // Place each found item that's different from current item into blacklist
                        $toExclude[$k] = $f;
                    }
                }
            }
        }
    }

    // Unset all keys that was found
    foreach($toExclude as $k => $v){
        unset($strs[$k]);
    }

    // Return the result
    return $strs;
}

$strs = array("Lincoln Crown","Crown Court","go holiday","house fire","John Hinton","Hinton Jailed");
print_r(cool_function($strs));

转储:

Array
(
    [0] => Lincoln Crown
    [2] => go holiday
    [3] => house fire
    [4] => John Hinton
)