这是我的练习，我有这样的文字:
"lovely heart"<<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="244546470a404142644c4b5049454d480a474b49" rel="noreferrer noopener nofollow">[email protected]</a>>,
"<<*>>Freeeky<<*>> Jack" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="4a2b2b282829290a2d272b232664292527" rel="noreferrer noopener nofollow">[email protected]</a>>,
"heavens's kingk*ng '-'asdf" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="71131313310810191e1e5f121e5f181f" rel="noreferrer noopener nofollow">[email protected]</a>>
"sample[^-^]"<<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="99eaf8f4e9f5fcd9eaeab7faf6f4" rel="noreferrer noopener nofollow">[email protected]</a>>
我只需要提取:
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="91f0f3f2bff5f4f7d1f9fee5fcf0f8fdbff2fefc" rel="noreferrer noopener nofollow">[email protected]</a>
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="7c1d1d1e1e1f1f3c1b111d1510521f1311" rel="noreferrer noopener nofollow">[email protected]</a>
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="a1c3c3c3e1d8c0c9cece8fc2ce8fc8cf" rel="noreferrer noopener nofollow">[email protected]</a>
<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="3340525e435f567340401d505c5e" rel="noreferrer noopener nofollow">[email protected]</a>
这是我的尝试，但仍然完成了一半或更少。
WITH t AS
(SELECT '"lovely heart"<<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="f3929190dd979695b39b9c879e929a9fdd909c9e" rel="noreferrer noopener nofollow">[email protected]</a>>,
"<<*>>Freeeky<<*>> Jack" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="dfbebebdbdbcbc9fb8b2beb6b3f1bcb0b2" rel="noreferrer noopener nofollow">[email protected]</a>>,
"heavens''s kingk*ng ''-''asdf" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="3e5c5c5c7e475f565151105d5153" rel="noreferrer noopener nofollow">[email protected]</a>>' word
FROM dual
)
SELECT regexp_substr(word, '<(.*@.*)>',1,LEVEL, NULL,1)
FROM t
CONNECT BY level <= regexp_count(word, '<(.*@.*)>');
一些结果如下:
<*>>Freeeky<<*>> Jack" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="9bfafaf9f9f8f8dbfcf6faf2f7b5f8f4f6" rel="noreferrer noopener nofollow">[email protected]</a>
请问有什么好的解决办法吗
谢谢
最佳答案
你的正则表达式的问题是，第一个 .*之后<将匹配 @ 之前的所有字符，作为 dot(.)正则表达式中的 可以匹配除换行符之外的任何字符。所以，它甚至会匹配 <和> 。以下是它与您的字符串的匹配方式:
'"< <<*>>Freeeky<<*>> Jack" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="7e1f1f1c1c1d1d3e19131f1712501d1113" rel="noreferrer noopener nofollow">[email protected]</a> >"'
^ ^ ^ ^
| ----------------------------------------- |
| | |
Match the first `<` (.*@.*) Match the last `>`.
因此，捕获的组是:
<<*>>Freeeky<<*>> Jack" <<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="4223232020212102252f232b2e6c212d2f" rel="noreferrer noopener nofollow">[email protected]</a>
这就是你得到的。您可以更改.*至[^<>]*匹配除 < 之外的任何字符和> :
使用以下正则表达式:
'<([^<>]*@[^<>]*)>'
关于sql - oracle正则表达式提取标签内的字符串，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18014379/