我有这样的表:
CREATE TABLE #Test
(
ParentID int,
DateCreated DATETIME,
ItemNo int
)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (1,'2008-10-01 00:00:00.000',0)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (1,'2008-10-01 00:00:00.000',1)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (1,'2008-05-01 00:00:00.000',2)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (1,'2008-05-01 00:00:00.000',3)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (2,'2008-06-01 00:00:00.000',3)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (2,'2008-06-01 00:00:00.000',4)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (2,'2008-04-01 00:00:00.000',6)
INSERT INTO #Test(ParentID, DateCreated, ItemNo) VALUES (2,'2008-04-01 00:00:00.000',8)
我需要一种在相同的parentID上选择最高的DateCreated和最高的ItemNo的方法,并且是否可以在查询中使用像这样的解决方案:
SELECT *
FROM #Test t
JOIN
(
If I could get maximum row here somehow that would be great
) maxt
ON t.ParentID = maxt.ParentID
JOIN SomeOtherTable sot
ON sot.DateCreated = maxt.MaxDateCreated
AND sot.ItemNo = maxt.MaxItemNo
GROUP BY
sot.Something
只是为了澄清结果应该是什么样子:
ParentID DateCreated ItemNo ParentID MaxDateCreated MaxItemNo
1, '2008-10-01 00:00:00.000' ,0 1, '2008-10-01 00:00:00.000',1
1, '2008-10-01 00:00:00.000' ,1 1, '2008-10-01 00:00:00.000',1
1, '2008-05-01 00:00:00.000' ,2 1, '2008-10-01 00:00:00.000',1
1, '2008-05-01 00:00:00.000' ,3 1, '2008-10-01 00:00:00.000',1
2, '2008-06-01 00:00:00.000' ,3 2, '2008-06-01 00:00:00.000',4
2, '2008-06-01 00:00:00.000' ,4 2, '2008-06-01 00:00:00.000',4
2, '2008-04-01 00:00:00.000' ,6 2, '2008-06-01 00:00:00.000',4
2, '2008-04-01 00:00:00.000' ,8 2, '2008-06-01 00:00:00.000',4
最佳答案
如果您需要 DateCreated 的最大值以及此 DateCreated 的最大 ItemNo:
select ParentId,
DateCreated as MaxDateCreated,
ItemNo as MaxItemNo
from
(select PArentID,DateCreated,ItemNo,
Row_Number() OVER (PARTITION BY ParentID
ORDER BY DateCreated DESC,
ItemNo Desc) as RN
from #Test
) t3
where RN=1
更新
要获得问题中提到的结果,您应该将其与 #TEST 一起加入,例如:
SELECT *
FROM Test t
JOIN
(
select ParentId,
DateCreated as MaxDateCreated,
ItemNo as MaxItemNo
from
(select PArentID,DateCreated,ItemNo,
Row_Number() OVER (PARTITION BY ParentID
ORDER BY DateCreated DESC,
ItemNo Desc) as RN
from test
) t3
where RN=1
) maxt
ON t.ParentID = maxt.ParentID
关于sql - 选择列上的 MAX,然后从依赖于第一个值的列中选择 MAX,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18123172/