我正在尝试编写一个简单的项目。我正在使用tomee
。 Tomee 工作正常,但我无法访问我的项目。当我尝试从浏览器访问我的项目时,Eclipse 控制台给出以下错误。
INFO: Server startup in 1661 ms
Dec 11, 2013 7:59:15 PM org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor processRequest
WARNING: No root resource matching request path has been found, Relative Path: /. Please enable FINE/TRACE log level for more details.
Dec 11, 2013 7:59:15 PM org.apache.cxf.jaxrs.impl.WebApplicationExceptionMapper toResponse
WARNING: javax.ws.rs.WebApplicationException
at org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.processRequest(JAXRSInInterceptor.java:162)
at org.apache.cxf.jaxrs.interceptor.JAXRSInInterceptor.handleMessage(JAXRSInInterceptor.java:91)
at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:262)
at org.apache.cxf.transport.ChainInitiationObserver.onMessage(ChainInitiationObserver.java:121)
at org.apache.cxf.transport.http.AbstractHTTPDestination.invoke(AbstractHTTPDestination.java:237)
at org.apache.openejb.server.cxf.rs.CxfRsHttpListener.onMessage(CxfRsHttpListener.java:170)
at org.apache.openejb.server.rest.RsServlet.service(RsServlet.java:53)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:51)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:243)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.tomee.catalina.OpenEJBValve.invoke(OpenEJBValve.java:45)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:100)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1041)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:603)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:312)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at java.lang.Thread.run(Thread.java:744)
最佳答案
如果您不指定应用程序,休息服务似乎会接管您的完整上下文,因此将下面的类添加到您的上下文中,它应该可以工作(它对我有用)。
@ApplicationPath("/rest")
public class ApplicationConfig extends Application {
}
http://openejb.979440.n4.nabble.com/No-root-resource-matching-request-path-td4666495.html
更新
或者,为了不在您的休息网址中出现丑陋的 /rest
部分:而不是为您的主 Web 应用程序指定 urlPatterns={"/*"}
(这与默认的休息应用程序冲突)您可以缩小范围,例如对于我的 vaadin 来说,到目前为止这是有效的:
@WebServlet(urlPatterns = {"", "/VAADIN/*", "/UIDL/*", "/HEARTBEAT/*"}
因此,您未为主应用程序更精确指定的所有内容都将转到其余应用程序。
关于eclipse - 为什么我收到 javax.ws.rs.WebApplicationException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20526674/