我有一些表单的大列表,其中的数据需要与其他同名表单中的其他数据连接起来。
列表格式相当复杂,如下所示:
[[{EVAL_SEQ_1, {FORMNAME, ListDataToConcat1}}], [{EVAL_SEQ_2, {FORMNAME, ListDataToConcat2}}], ...]
这是我想要的输出:
[[{EVAL_SEQ_1, {FORMNAME, ListDataToConcat1 + ListDataToConcat2}}]}}] ...]
地点:
EVAL_SEQ_1 = Form Sequence Number,
FORMNAME = Form Name
ListDataToConcat = List that Needs to concat
例如,这是我的示例数据:
[[{"eval_data_12",
{<<"prvl_mobable_asset_0000_h200401">>,
[{'F_01_0100',[1]},
{'F_01_0090',["3"]},
{'F_01_0080',[]},
{'F_01_0070',[9999]},
{'F_01_0060',[{era,0},{year,[]},{month,[]}]},
{'F_01_0050',[]},
{'F_01_0040',[]},
{'F_01_0030',[]},
{'F_01_0020',<<>>},
{'F_01_0010',<<"4 - 8">>}]}}],
[{"eval_data_11",
{<<"prvl_mobable_asset_0000_h200401">>,
[{'F_01_0100',[]},
{'F_01_0090',["2"]},
{'F_01_0080',[]},
{'F_01_0070',[22222]},
{'F_01_0060',[{era,0},{year,[]},{month,[]}]},
{'F_01_0050',[]},
{'F_01_0040',[]},
{'F_01_0030',[]},
{'F_01_0020',<<>>},
{'F_01_0010',<<"4 - 1">>}]}}], ...]
我想要这样的结果输出:
[{"eval_data_11",
{<<"prvl_mobable_asset_0000_h200401">>,
[{'F_01_0100',[[], [1]]},
{'F_01_0090',[["2"], ["3"]]},
{'F_01_0080',[[], []]},
{'F_01_0070',[[22222], [9999]]},
{'F_01_0060',[[{era,0},{year,[]},{month,[]}], [{era,0},{year,[]},{month,[]}]]},
{'F_01_0050',[[], []]},
{'F_01_0040',[[], []]},
{'F_01_0030',[[], []]},
{'F_01_0020',[[<<>>], [<<>>]]},
{'F_01_0010',[[<<"4 - 1">>], [<<"4 - 8">>]}]}}]
最佳答案
我向您建议这个解决方案:
[编辑]
我修改了代码来回答你最后的评论,仍然有模糊的地方:
- 如果 Assets 不同,会创建不同的记录列表吗?
- 如果不是,应该如何处理 Assets 名称?我选择保留“最小的”
- 记录的顺序重要吗 - 我决定不重要
需要注意的是,我缺少一些上下文,但是如果我添加收集此类信息,我会将其存储在 ets 表中。它更新速度更快,易于遍历,并且在需要时易于转换为列表。
-module (t).
-compile([export_all]).
% rec = {atom,term}
% reclist = [rec,...]
% asset = {bin,reclist}
% eval_data = [{list,asset}]
% eval_set = [eval_data,...]
% recs = {atom,[term]}
% recslist = [recs,...]
addrec({Key,Val},Recslist) ->
Val_list = proplists:get_value(Key, Recslist, []),
[{Key,[Val|Val_list]}|proplists:delete(Key,Recslist)].
merge_rec(Reclist,Recslist) -> lists:foldl(fun(Rec,Acc) -> addrec(Rec,Acc) end,Recslist,Reclist).
merge_eval([{Eval,{Asset,Reclist}}],[]) ->
[{Eval,{Asset,[{Key,[Val]} || {Key,Val} <- Reclist]}}];
merge_eval([{Eval,{Asset,Reclist}}],[{Eval_low,{Asset_low,Recslist}}]) ->
[{min(Eval,Eval_low),{min(Asset,Asset_low),merge_rec(Reclist,Recslist)}}].
merge_set(Eval_set) -> lists:foldl(fun(Eval_data,Acc) -> merge_eval(Eval_data,Acc) end,[],Eval_set).
test() ->
Eval_set = [[{"eval_data_10",
{<<"prvl_mobable_asset_0000_h200401">>,
[{'F_01_0100',[1]},
{'F_01_0090',["3"]},
{'F_01_0080',[]},
{'F_01_0070',[9999]},
{'F_01_0060',[{era,0},{year,[]},{month,[]}]},
{'F_01_0050',[]},
{'F_01_0040',[]},
{'F_01_0030',[]},
{'F_01_0020',<<>>},
{'F_01_0010',<<"4 - 8">>}]}}],
[{"eval_data_11",
{<<"prvl_mobable_asset_0000_h200401">>,
[{'F_01_0100',[]},
{'F_01_0090',["2"]},
{'F_01_0080',[]},
{'F_01_0070',[22222]},
{'F_01_0060',[{era,0},{year,[]},{month,[]}]},
{'F_01_0050',[]},
{'F_01_0040',[]},
{'F_01_0030',[]},
{'F_01_0020',<<>>},
{'F_01_0010',<<"4 - 1">>}]}}]],
merge_set(Eval_set).
关于erlang - Erlang 内部列表的自定义串联,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23340668/