如何在构建时获取 SBT 暂存目录?
我想要对远程存储库进行棘手的克隆,而 SBT 的 stagingDirectory
似乎非常合适。
如何获取“Build.scala”内的目录?
SBT源代码: http://www.scala-sbt.org/0.13.1/sxr/sbt/BuildPaths.scala.html#sbt.BuildPaths.stagingDirectory
=======
根本问题与问题不直接相关。我想在 SBT 中使用 git 依赖项的子目录。 SBT 不提供开箱即用的功能,因此我编写了一个简单的包装器:
object Git {
def clone(cloneFrom: String, branch: String, subdirectory: String) = {
val uniqueHash = Hash.halfHashString(cloneFrom + branch)
val cloneTo = file(sys.props("user.home")) / ".sbt" / "staging" / uniqueHash
val clonedDir = creates(cloneTo) {
Resolvers.run("git", "clone", cloneFrom, cloneTo.absolutePath)
Resolvers.run(Some(cloneTo), "git", "checkout", "-q", branch)
}
clonedDir / subdirectory
}
}
用法:
lazy val myDependency = Git.clone(cloneFrom = "git://...someproject.git",branch = "v2.4", subdirectory = "someModule")
最佳答案
从链接中查看 API,您可以使用 getGlobalBase
和 getStagingDirectory
两种方法,两者都采用状态。
import sbt._
import Keys._
import sbt.BuildPaths._
object MyBuild extends Build {
val outputStaging = taskKey[Unit]("Outputs staging")
lazy val root = project.in(file(".")).settings(
outputStaging := {
val s = state.value
println(getStagingDirectory(s, getGlobalBase(s)))
}
)
}
编辑
在您上次评论后,我认为您正在寻找 custom resolver 。自定义解析器可以访问 ResolveInfo对象,它有一个名为 staging
的属性。
例如,您可以通过以下方式实现您正在寻找的目标(实际上无需直接访问 staging
):
object MyBuild extends Build {
lazy val root = project.in(file(".")).dependsOn(RootProject(uri("dir+git://github.com/lpiepiora/test-repo.git#branch=master&dir=subdir")))
override def buildLoaders = BuildLoader.resolve(myCustomGitResolver) +: super.buildLoaders
def myCustomGitResolver(info: BuildLoader.ResolveInfo): Option[() => File] =
if(info.uri.getScheme != "dir+git") None
else {
import RichURI.fromURI
val uri = info.uri
val (branch, directory) = parseOutBranchNameAndDir(uri.getFragment)
val gitResolveInfo = new BuildLoader.ResolveInfo(
uri.copy(scheme = "git", fragment = branch), info.staging, info.config, info.state
)
println(uri.copy(scheme = "git", fragment = branch))
Resolvers.git(gitResolveInfo).map(fn => () => fn() / directory)
}
// just an ugly way to get the branch and the folder
// you may want something more sophisticated
private def parseOutBranchNameAndDir(fragment: String): (String, String) = {
val Array(branch, dir) = fragment.split('&')
(branch.split('=')(1), dir.split('=')(1))
}
}
我们的想法是,我们委托(delegate)给预定义的 git 解析器,然后让它完成工作,完成后,我们将返回一个子目录:fn()/directory
。
这是一个示例,当然您可以坚持获取存储库的逻辑。 暂存目录将在解析器方法中可供您使用。
关于scala - 如何在构建时获取 SBT 暂存目录?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23932906/