我正在学习如何在 python 中执行 SQL(我知道 SQL,而不是 Python)。
我有一个外部 sql 文件。它创建数据并将数据插入到三个表“Zookeeper”、“Handles”、“Animal”中。
然后我有一系列查询要运行表。以下查询位于我在 python 脚本顶部加载的 zookeeper.sql 文件中。前两个的例子是:
--1.1
SELECT ANAME,zookeepid
FROM ANIMAL, HANDLES
WHERE AID=ANIMALID;
--1.2
SELECT ZNAME, SUM(TIMETOFEED)
FROM ZOOKEEPER, ANIMAL, HANDLES
WHERE AID=ANIMALID AND ZOOKEEPID=ZID
GROUP BY zookeeper.zname;
这些都在 SQL 中执行得很好。现在我需要从 Python 中执行它们。我已经获得并完成了读取文件的代码。然后执行循环中的所有查询。
1.1 和 1.2 是我感到困惑的地方。我相信在循环中,这是我应该放入一些东西来运行第一个和第二个查询的行。
result = c.execute("SELECT * FROM %s;"% table);
但是什么?我想我错过了一些非常明显的东西。我认为让我失望的是 % table。在查询 1.1 和 1.2 中,我不是在创建表,而是在查找查询结果。
我的整个python代码如下。
import sqlite3
from sqlite3 import OperationalError
conn = sqlite3.connect('csc455_HW3.db')
c = conn.cursor()
# Open and read the file as a single buffer
fd = open('ZooDatabase.sql', 'r')
sqlFile = fd.read()
fd.close()
# all SQL commands (split on ';')
sqlCommands = sqlFile.split(';')
# Execute every command from the input file
for command in sqlCommands:
# This will skip and report errors
# For example, if the tables do not yet exist, this will skip over
# the DROP TABLE commands
try:
c.execute(command)
except OperationalError, msg:
print "Command skipped: ", msg
# For each of the 3 tables, query the database and print the contents
for table in ['ZooKeeper', 'Animal', 'Handles']:
**# Plug in the name of the table into SELECT * query
result = c.execute("SELECT * FROM %s;" % table);**
# Get all rows.
rows = result.fetchall();
# \n represents an end-of-line
print "\n--- TABLE ", table, "\n"
# This will print the name of the columns, padding each name up
# to 22 characters. Note that comma at the end prevents new lines
for desc in result.description:
print desc[0].rjust(22, ' '),
# End the line with column names
print ""
for row in rows:
for value in row:
# Print each value, padding it up with ' ' to 22 characters on the right
print str(value).rjust(22, ' '),
# End the values from the row
print ""
c.close()
conn.close()
最佳答案
您的代码已经包含了一种从指定的 sql 文件执行所有语句的漂亮方法
# Open and read the file as a single buffer
fd = open('ZooDatabase.sql', 'r')
sqlFile = fd.read()
fd.close()
# all SQL commands (split on ';')
sqlCommands = sqlFile.split(';')
# Execute every command from the input file
for command in sqlCommands:
# This will skip and report errors
# For example, if the tables do not yet exist, this will skip over
# the DROP TABLE commands
try:
c.execute(command)
except OperationalError, msg:
print("Command skipped: ", msg)
将其包装在一个函数中,您可以重复使用它。
def executeScriptsFromFile(filename):
# Open and read the file as a single buffer
fd = open(filename, 'r')
sqlFile = fd.read()
fd.close()
# all SQL commands (split on ';')
sqlCommands = sqlFile.split(';')
# Execute every command from the input file
for command in sqlCommands:
# This will skip and report errors
# For example, if the tables do not yet exist, this will skip over
# the DROP TABLE commands
try:
c.execute(command)
except OperationalError, msg:
print("Command skipped: ", msg)
使用它
executeScriptsFromFile('zookeeper.sql')
你说你被弄糊涂了
result = c.execute("SELECT * FROM %s;" % table);
在 Python 中,您可以使用称为字符串格式化的方法向字符串添加内容。
你有一个字符串 "Some string with %s"
和 %s,这是其他东西的占位符。要替换占位符,请在字符串后添加 %(“你想用什么替换它”)
例如:
a = "Hi, my name is %s and I have a %s hat" % ("Azeirah", "cool")
print(a)
>>> Hi, my name is Azeirah and I have a Cool hat
有点幼稚的例子,但应该很清楚。
现在,什么
result = c.execute("SELECT * FROM %s;" % table);
意思是,是不是用表变量的值代替了%s。
(创建于)
for table in ['ZooKeeper', 'Animal', 'Handles']:
# for loop example
for fruit in ["apple", "pear", "orange"]:
print(fruit)
>>> apple
>>> pear
>>> orange
如果您还有其他问题,请戳我。
关于python - 在python中读取外部sql脚本,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19472922/