我正在尝试使我的数据集与此示例相对应:
var family = [{
"name" : "Jason",
"age" : "24",
"gender" : "male"
},
{
"name" : "Kyle",
"age" : "21",
"gender" : "male"
}];
我有一个名称 Map<String, HashSet<String>>
和与这些名称可以引用的特定实体相对应的唯一字母数字值,我们将这些条目称为“ID”。
例如, Fyodor Mikhailovich Dostoyevsky
可能与 ID Q626
相关,因为这是一个非常具体的引用,没有很多广为人知的数字具有该名称。然而, Bush
可能附加到 G027
、 Q290
和 Q118
,可能引用了男人、啤酒和灌木,没有特定的顺序。
它看起来像这样(真正的要大得多):
[Rao=[Q7293658, , Q7293657, Q12953055, Q3531237, Q4178159, Q1138810, Q579515, Q3365064, Q7293664, Q1133815], Hani Durzy=[], Louise=[, Q1660645, Q130413, Q3215140, Q152779, Q233203, Q7871343, Q232402, Q82547, Q286488, Q156723, Q3263649, Q456386, Q233192, Q14714149, Q12125864, Q57669, Q168667, Q141410, Q166028], Reyna=[Q7573462, Q2892895, Q363257, Q151944, Q3740321, Q2857439, Q1453358, Q7319529, Q733716, Q16151941, Q7159448, Q5484172, Q6074271, Q1753185, Q7319532, Q5171205, Q3183869, Q1818527, Q251862, Q3840414, Q5271282, Q5606181]]
使用 jackson 我尝试这样:
Map<String, HashSet<String>> map = q_valMap;
mapper.writeValue(new File("JSON_Output/user.json"), map);
但这似乎是错误的,因为我的输出都混杂在一起,即
{"Rao":["Q7293658","","Q7293657","Q12953055","Q3531237","Q4178159","Q1138810","Q579515","Q3365064","Q7293664","Q1133815"],"Hani Durzy":[""],"Louise":["","Q1660645","Q130413","Q3215140","Q152779","Q233203","Q7871343","Q232402","Q82547","Q286488","Q156723","Q3263649","Q456386","Q233192","Q14714149","Q12125864","Q57669","Q168667","Q141410","Q166028"],"Reyna":["Q7573462","Q2892895","Q363257","Q151944","Q3740321","Q2857439","Q1453358","Q7319529","Q733716","Q16151941","Q7159448","Q5484172","Q6074271","Q1753185","Q7319532","Q5171205","Q3183869","Q1818527","Q251862","Q3840414","Q5271282","Q5606181"]}
我是否只需迭代地填充此 JSON 对象?
就像上面的例子一样,我认为它应该看起来像这样,尽管接下来的只是一个伪代码特征,也就是说,不完全是这样,而是类似的东西:
{
key: "Rao"
value: ["Q7293658","","Q7293657","Q12953055","Q3531237","Q4178159","Q1138810","Q579515","Q3365064","Q7293664","Q1133815"]
key: "Hani Durzy"
value: [""]
key: "Louise"
value: ["","Q1660645","Q130413","Q3215140","Q152779","Q233203","Q7871343","Q232402","Q82547","Q286488","Q156723","Q3263649","Q456386","Q233192","Q14714149","Q12125864","Q57669","Q168667","Q141410","Q166028"]
key: "Reyna"
value: ["Q7573462","Q2892895","Q363257","Q151944","Q3740321","Q2857439","Q1453358","Q7319529","Q733716","Q16151941","Q7159448","Q5484172","Q6074271","Q1753185","Q7319532","Q5171205","Q3183869","Q1818527","Q251862","Q3840414","Q5271282","Q5606181"]
}
这不对吗?
更新
public class JsonMapFileExample
{
public static void map(Map<String, HashSet<String>> q_valMap )
{
ObjectMapper mapper = new ObjectMapper();
ArrayNode array = mapper.createArrayNode();
for ( Entry entry: q_valMap.entrySet() )
{
ObjectNode node = mapper.createObjectNode()
.put("name", entry.getKey())
.put("ids", entry.getValue());
array.add(node);
}
mapper.writeValue("/home/matthias/Workbench/SUTD/nytimes_corpus/wdtk-parent/wdtk-examples/JSON_Output/user.json", array);
}
}
class MyEntity
{
private String name;
Set<String> value; // use names that you want in the result JSON
//constructors
public MyEntity()
{
}
public MyEntity(String name)
{
this.name = name;
}
//getters
public String getName()
{
return this.name;
}
public Set<String> getValue()
{
return this.value;
}
//setters
public void setName(String name)
{
this.name = name;
}
public void setValue(Set<String> value)
{
this.value = value;
}
}
最佳答案
您可以手动设置键名称,例如:
ArrayNode array = mapper.createArrayNode();
for (Entry entry: yourMap.entries()) {
ObjectNode node = mapper.createObjectNode()
.put("name", entry.key())
.putPOJO("ids", entry.value());
array.add(node);
}
mapper.writeValue(file, array);
或者,您可以为您的数据创建一个类
class MyEntity {
String name;
Set<String> ids; // use names that you want in the JSON result
// getters, setters if necessary
}
将数据映射转换为 MyEntity
列表,然后使用 Jackson ObjectMapper
创建 JSON,如 mapper.writeValue(file, listOfMyEntities)
,输出如下
[
{
"name": "some name here",
"ids": ["id1", "id2", ...]
}
// more elements here
]
关于json - 将 <String、HashSet<String>> 映射到 JSON 和 pretty-print ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29838841/