c# - 使用 XmlSerializer 将 DataTable 反序列化为自定义类

Question

是否可以将 DataTable 反序列化为自定义类？一个 SOAP 请求以这种格式返回 DataTable

<xs:schema xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" id="NewDataSet">
  <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:MainDataTable="geolocation" msdata:UseCurrentLocale="true">
    <xs:complexType>
      <xs:choice minOccurs="0" maxOccurs="unbounded">
        <xs:element name="geolocation">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="Latitude" type="xs:float" minOccurs="0"/>
              <xs:element name="Longitude" type="xs:float" minOccurs="0"/>
            </xs:sequence>
          </xs:complexType>
        </xs:element>
      </xs:choice>
    </xs:complexType>
  </xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
  <NewDataSet xmlns="">
     <geolocation diffgr:id="geolocation" msdata:rowOrder="0">
       <Latitude>48.8186</Latitude>
       <Longitude>28.4681</Longitude>
     </geolocation>
     ...
  </NewDataSet>
</diffgr:diffgram>

我想将其反序列化为数组

public class Geolocation {
    public double latitude { get; set; }
    public double longitude { get; set; }
}

使用 XmlSerializer

XmlSerializer serializer = new XmlSerializer(typeof(Geolocation[]))
var Geolocations = (Geolocation)serializer.Deserialize(stream);

编辑:我尝试做这样的事情:

public class Geolocation {
    [XmlElement("Latitude")]
    public double Latitude { get; set; }
    [XmlElement("Longitude")]
    public double Longitude { get; set; }
}

但这没有用

Answer 1

在aevitas的帮助下和一些更多的研究我终于成功做到了，首先像这样写下你的服务引用

public class DataTable
{
    [XmlElement(ElementName = "schema", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Schema Schema { get; set; }
    [XmlElement(ElementName = "diffgram", Namespace="urn:schemas-microsoft-com:xml-diffgram-v1")]
    public Diffgram Diffgram { get; set; }
}

public class Schema
{
    [XmlElement(ElementName = "element", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Element Element { get; set; }
}

public class Element
{
    [XmlElement(ElementName = "complexType", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public ComplexType ComplexType { get; set; }
    [XmlAttribute(AttributeName = "name", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public String Name { get; set; }
}

public class ComplexType
{
    [XmlElement(ElementName = "choice", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Choice Choice { get; set; }
    [XmlElement(ElementName = "sequence", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Sequence Sequence { get; set; }
}

public class Sequence
{
    [XmlElement(ElementName = "element", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Element[] Elements { get; set; }
}

public class Choice
{
    [XmlElement(ElementName = "element", Namespace = "http://www.w3.org/2001/XMLSchema")]
    public Element Element { get; set; }
}

public classDiffgram
{
    [XmlElement(ElementName = "NewDataSet", Namespace = "")]
    public NewDataSet NewDataSet { get; set; }
}

public class NewDataSet
{
    [XmlElement("geolocation")]
    public Geolocation[] Geolocations { get; set; }
}

public class Geolocation
{
    [XmlElement("Latitude")]
    public double Latitude { get; set; }
    [XmlElement("Longitude")]
    public double Longitude { get; set; }
}

然后就写

// Namespace url is optional
XmlSerializer serializer = new XmlSerializer(typeof(DataTable), "http://example.com");
DataTable dt = (DataTable)serializer.Deserialize(stream);