php - 值(value)比较未按预期进行

Question

我尝试根据两个值显示不同的颜色。

首先，如果值相等，则显示绿色，效果很好

  <?php if (miletofurlong($pasthorse['distance']) == $todaysdistance)
    {
      $Horsedist = "<b><span style='color:#ff4500 '>". miletofurlong($pasthorse['distance'])."f</span></b>";
    } ?>

现在我想做的是如果 miletofurlong($pasthorse['distance']) 不等于但仍介于 ($todaysdistance + 1) 和 ($todaysdistance + 1) 之间)然后将其突出显示为蓝色。

我运行了以下代码，但它似乎突出显示了所有内容，我不确定为什么

if (miletofurlong($pasthorse['distance']) == $todaysdistance)
    {
    $Horsedist = "<b><span style='color:#ff4500 '>". miletofurlong($pasthorse['distance'])."f</span></b>";
    }
    elseif (miletofurlong($pasthorse['distance']) !== $todaysdistance and miletofurlong($pasthorse['distance']) <= ($todaysdistance + 1) or miletofurlong($pasthorse['distance']) !== $todaysdistance and miletofurlong($pasthorse['distance']) >= ($todaysdistance - 1)  )
    {
    $Horsedist = "<b><span style='color:blue'>". miletofurlong($pasthorse['distance'])."f</span></b>". ($todaysdistance + 1). "and" . ($todaysdistance - 1);
    }
    else
    {
    $Horsedist = miletofurlong($pasthorse['distance'])."f" ;
    }

Answer 1

您缺少括号，并且您的 if 情况有点困惑。让我们首先使用一个变量并在其中声明您的 $pasthorse。

$distance = miletofurlong($ pasthorse['distance']);
if ($distance == $todaysdistance)
    $Horsedist = "<b><span style='color:#ff4500 '>". $distance ."f</span></b>";
else if ($distance <= ($todaysdistance + 1) and $distance >= ($todaysdistance - 1)  )
    $Horsedist = "<b><span style='color:blue'>". $distance . "f</span></b>"  ($todaysdistance + 1). "and" . ($todaysdistance - 1);
else
    $Horsedist = $distance ."f" ;

这样，它应该工作得更好，并且更具可读性。