我想使用 qdap 包在 R 中进行情感分析。
它给出一个包含 all.all、all.wc、all.polity、all.pos.words、all.neg.words 等的数据框。
我想提取 all.polity、all.pos.words、all.neg.words 的值，但是当我使用 情感$all.极性或情感$all.pos.words，
结果为 NULL。
dput(head(sentiment))
list(structure(list(all = c("all", "all", "all"), wc = c(44L,
1L, 1L), polarity = c(-0.422115882408869, 0, 0), pos.words = list(
"-", "-", "-"), neg.words = list(c("disappointed", "issue"
), "-", "-"), text.var = c("list(list(content = \" misleaded icici bank customer care branch excutive really disappointed bank dont know steps take get issue fixed\", meta = list(author = character(0), datetimestamp = list(sec = 20.097678899765, min = 51, hour = 11, mday = 6, mon = 6, year = 115, wday = 1, yday = 186, isdst = 0), description = character(0), heading = character(0), id = \"1\", language = \"en\", origin = character(0))))",
"list()", "list()")), row.names = c(NA, -3L), .Names = c("all",
"wc", "polarity", "pos.words", "neg.words", "text.var"), class = "data.frame"),
structure(list(all = c("all", "all", "all"), wc = c(61L,
1L, 1L), polarity = c(0, 0, 0), pos.words = list("led", "-",
"-"), neg.words = list("expire", "-", "-"), text.var = c("list(list(content = \" didnt know customer banking icici years will led people looking student travel card staff mg road treat customers tried offer card wud expire one year n told get new card one year dont know\", meta = list(author = character(0), datetimestamp = list(sec = 20.3989679813385, min = 51, hour = 11, mday = 6, mon = 6, year = 115, wday = 1, yday = 186, isdst = 0), description = character(0), heading = character(0), id = \"1\", language = \"en\", origin = character(0))))",
"list()", "list()")), row.names = c(NA, -3L), .Names = c("all",
"wc", "polarity", "pos.words", "neg.words", "text.var"), class = "data.frame"),
structure(list(all = c("all", "all", "all"), wc = c(58L,
1L, 1L), polarity = c(0, 0, 0), pos.words = list("top", "-",
"-"), neg.words = list("worst", "-", "-"), text.var = c("list(list(content = \" asked staff can upgrade platinum coral card documentation fee will involoved even receiving card poeple sill keep calling top levied rs joining fee interested paying card one worst customer care experienced\", meta = list(author = character(0), datetimestamp = list(sec = 20.648964881897, min = 51, hour = 11, mday = 6, mon = 6, year = 115, wday = 1, yday = 186, isdst = 0), description = character(0), heading = character(0), id = \"1\", language = \"en\", \n origin = character(0))))",
"list()", "list()")), row.names = c(NA, -3L), .Names = c("all",
"wc", "polarity", "pos.words", "neg.words", "text.var"), class = "data.frame"),
structure(list(all = c("all", "all", "all"), wc = c(59L,
1L, 1L), polarity = c(-0.494717861727131, 0, 0), pos.words = list(
"-", "-", "-"), neg.words = list(c("long time", "long time",
"disappointed"), "-", "-"), text.var = c("list(list(content = \" applied credit card corporate scheme long time back got verification call also long time back initially getting least response executive now longer picking call neither letting know status application extremely disappointed service\", meta = list(author = character(0), datetimestamp = list(sec = 20.8989698886871, min = 51, hour = 11, mday = 6, mon = 6, year = 115, wday = 1, yday = 186, isdst = 0), description = character(0), heading = character(0), id = \"1\", \n language = \"en\", origin = character(0))))",
"list()", "list()")), row.names = c(NA, -3L), .Names = c("all",
"wc", "polarity", "pos.words", "neg.words", "text.var"), class = "data.frame"),
structure(list(all = c("all", "all", "all"), wc = c(66L,
1L, 1L), polarity = c(0.0246182981958665, 0, 0), pos.words = list(
c("work", "support"), "-", "-"), neg.words = list("disappointed",
"-", "-"), text.var = c("list(list(content = \" otp service working used work month decided change everything im getting otp sms registered mobile number ive tried contacting customer support several times keep asking send sms despite done several times several days havent received otps ever really disappointed\", meta = list(author = character(0), datetimestamp = list(sec = 21.1935319900513, min = 51, hour = 11, mday = 6, mon = 6, year = 115, wday = 1, yday = 186, isdst = 0), description = character(0), \n heading = character(0), id = \"1\", language = \"en\", origin = character(0))))",
"list()", "list()")), row.names = c(NA, -3L), .Names = c("all",
"wc", "polarity", "pos.words", "neg.words", "text.var"), class = "data.frame"),
structure(list(all = c("all", "all", "all"), wc = c(50L,
1L, 1L), polarity = c(-0.282842712474619, 0, 0), pos.words = list(
"-", "-", "-"), neg.words = list(c("pathetic", "lied"
), "-", "-"), text.var = c("list(list(content = \" pathetic service behavior icici bank facing past days icici executive lied luring upgrade debit card terms conditions just opposite booklet received told phone\", meta = list(author = character(0), datetimestamp = list(sec = 21.4258019924164, min = 51, hour = 11, mday = 6, mon = 6, year = 115, wday = 1, yday = 186, isdst = 0), description = character(0), heading = character(0), id = \"1\", language = \"en\", origin = character(0))))",
"list()", "list()")), row.names = c(NA, -3L), .Names = c("all",
"wc", "polarity", "pos.words", "neg.words", "text.var"), class = "data.frame"))
有人可以建议如何做到这一点吗？
最佳答案
以下内容对我有用 -
library(qdap)
text <- "I am liking the work " # the text for which polarity score is needed
sentiment <- polarity(text) #make the call
sentiment$all$pos.words # returns the positive words detected by the algo
#[[1]]
#[1] "liking" "work"
sentiment$all$polarity # returns the sentence polarity score
#[1] 0.8944272
关于r - 从 R 中的 qdap 包结果中获取 all.polity 值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31242629/