r - 条件格式 FlexTable

Question

我正在寻找一种使用百分比数字通过 ReporteR 有条件地格式化弹性表的方法。下面是一个小例子。

packs <- list("ReporteRs","scales")
lapply(packs,require,character.only = TRUE)

dat <- cbind.data.frame(rep("ABCD",2),c(0.07,0.11),c(0.03,0.01))
colnames(dat) <- c("A","B","C")
dat[,2] <- percent(dat[,2])

pp = pptx()
pp = addSlide(pp, "Title and Content")
datft = FlexTable(data = dat)
cname <- c("B","C") 

for (i in cname) {
   if (i=="B") {
   datft[dat[, i] <= 10, i] = cellProperties( background.color = "green" )
   datft[dat[, i] > 10, i] = cellProperties( background.color = "red" )
   } else if (i=="C") {
   datft[dat[, i] <= 0.02, i] = cellProperties( background.color = "green" )
   datft[dat[, i] > 0.02, i] = cellProperties( background.color = "red" )   
   }
}
pp = addFlexTable(pp, datft)
writeDoc(pp, paste(getwd(),"/example.pptx",sep=""))

这对于 C 列效果很好，但显然不适用于 B 列，因为它不是数字。我无法找到一种方法来应用在更改背景颜色后将值格式化为百分比数字的函数。

Answer 1

试试这个(在评论中给出解释，但经过测试):

for (i in cname) {
   if (i=="B") {
   datft[as.numeric( sub("%", "", dat[, i])) <= 10, i] = cellProperties( background.color = "green" )
   datft[ as.numeric( sub("%", "", dat[, i])) > 10, i] = cellProperties( background.color = "red" )
   } else if (i=="C") {
   datft[dat[, i] <= 0.02, i] = cellProperties( background.color = "green" )
   datft[dat[, i] > 0.02, i] = cellProperties( background.color = "red" )   
   }
}