<?php
function render_links($page, $level = 0) {
echo "<li>";
echo "<a href=''>" . get_the_title( $page ) . "</a>";
$children = get_pages("child_of=" . $page->id . "&parent=0");
if (!empty($children)) {
echo "<ul>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
echo "</li>";
}
echo "<ul>";
foreach (get_pages("parent=0") as $p) {
render_links($top_level);
}
echo "</ul>";
?>
这是我尝试渲染父级和子级,但是它只是在很多 li 中循环出当前页面标题。
有人可以帮助我吗?
更新:
<?php
function render_links($page, $level = 0) {
echo "<li>";
echo "<a href=''>" . get_the_title( $page ) . "</a>";
$children = get_pages("child_of=" . $page->id);
if (!empty($children)) {
echo "<ul>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
echo "</li>";
}
echo "<ul>";
foreach (get_pages("parent=0") as $p) {
render_links($top_level);
}
echo "</ul>";
?>
尝试此操作时,它会正确循环出当前页面,然后向相同的子页面发送垃圾邮件(即使只有 1 个子页面)。
但是,它没有列出网站上的其他父页面。 看图: https://gyazo.com/93728738fadc3c6e97ed18d20a46d273
渲染后出现此错误:
Fatal error: Maximum function nesting level of '100' reached, aborting! in C:\wamp\www\yangtorp\wp-includes\cache.php on line
更新:
<?php
function render_links($pge, $level = 0) {
echo "<li>";
echo "<a href=''>" . $pge->post_title . "</a>";
$children = get_pages( array( 'child_of' => $post->ID, 'sort_column' => 'post_date', 'sort_order' => 'desc' ) );
if (!empty($children) && $level != 2) {
echo "<ul class='sub-menu'>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
else{
echo "</li>";
}
}
echo "<ul id='menu-main' class='menu'>";
foreach (get_pages("parent=0") as $p) {
render_links($p);
}
echo "</ul>";
?>
又近了一步。现在它列出了父页面,并正确显示名称。但是我无法让它工作:
$children = get_pages("child_of=" . $page->id . "&parent=0");
最佳答案
我认为你应该这样做:
if (!empty($children)) {
echo "<ul>";
foreach ($children as $c) {
render_links($c, $level + 1);
}
echo "</ul>";
}
//missing else case
else{
echo "</li>";
}
关于php - 循环出 WordPress 菜单项和子菜单项,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32309959/