matlab - 如何找到两个矩阵之间最近的两个点？

Question

我有

X = (Yt.*sin(W))-(Xt.*cos(W));
Y = (Yt.*cos(W))+(Xt.*sin(W));  % which give the coordinates X and Y. 
X_inv = R.*sin(B_involute); 
Y_inv = R.*cos(B_involute);     % which give the coordinates X_inv and Y_inv.

我需要找到X、Y和X_inv、Y_inv之间最近的两个点。

从现在开始非常感谢。

Answer 1

您可以使用 pdist2 有效计算成对距离

D = pdist2( [X(:) Y(:)], [X_inv(:) Y_inv(:)] );

一旦获得了成对距离，就很容易找到最小距离

[md mi] = min(D(:));

将线性索引转换为对索引

[idx, inv_idx] = ind2sub( size(D), mi );

结果

fprintf(1, 'Closest points are [%d]: (%f,%f) -> [%d]: (%f,%f)\n',...
        idx, X(idx), Y(idx), inv_idx, X_inv(inv_idx), Y_inv(inv_idx) );