我从 xml 中进行选择,它将属性解析为如下列:
declare @xml xml
select @xml = xml_Function()
SELECT
Tab.Col.value('@fieldOne','varchar(20)') AS fieldOne,
Tab.Col.value('@fieldTwo','varchar(20)') AS fieldTwo
FROM @xml.nodes('/row') Tab(Col)
是否可以直接从 xml_Function
进行选择,而不将结果复制到 @xml
变量中?
类似于:
SELECT *
FROM xml_Function().nodes('/row')
最佳答案
据我所知,您不能直接将 XML 返回函数与 nodes()
一起使用,但您可以使用 CTE 或“子选择”来内联它:
CREATE FUNCTION dbo.ComeBackAsXML(@XmlText VARCHAR(MAX))
RETURNS XML
AS
BEGIN
DECLARE @x XML=CAST(@XmlText AS XML);
RETURN @x;
END
GO
DECLARE @xText VARCHAR(MAX)=
'<root>
<item id="3">
<a attr="test1" />
<a attr="test2" />
<a attr="test3" />
</item>
<item id="5">
<a attr="test1" />
<a attr="test2" />
</item>
</root>';
WITH GetXml AS (SELECT dbo.ComeBackAsXml(@xText) AS AsXml)
SELECT item.value('@id','int') AS ItemID
,a.value('@attr','varchar(max)') AS a_Attr
FROM GetXml
CROSS APPLY GetXml.AsXml.nodes('/root/item') AS One(item)
CROSS APPLY One.item.nodes('a') AS The(a);
GO
DROP FUNCTION dbo.ComeBackAsXML;
GO
这是作为子选择的 CTE:
SELECT item.value('@id','int') AS ItemID
,a.value('@attr','varchar(max)') AS a_Attr
FROM (SELECT dbo.ComeBackAsXml(@xText)) AS GetXml(AsXml)
CROSS APPLY GetXml.AsXml.nodes('/root/item') AS One(item)
CROSS APPLY One.item.nodes('a') AS The(a);
如果您想让函数可参数化,您必须注意,您写入 XPath 表达式的内容(几乎在所有情况下)都是文字,因此不可参数化...
我假设您不希望使用“通用”XML 函数来处理您可能需要的任何未知结构。我假设有一个给定的 XML 始终相同,而您只想将查询写得更短:
你有好几条路要走
- 交付表格并使用
WHERE
- 传入参数并将其与
sql:parameter()
一起使用 - 动态构建语句(需要存储过程)
在这里您可以找到每种方法的示例:
CREATE FUNCTION dbo.ParseXML(@xml XML)
RETURNS TABLE
AS
RETURN
SELECT item.value('@id','int') AS ItemID
,a.value('@attr','varchar(max)') AS a_Attr
FROM @xml.nodes('/root/item') AS One(item)
CROSS APPLY One.item.nodes('a') AS The(a);
GO
DECLARE @x XML=
'<root>
<item id="3">
<a attr="test1" />
<a attr="test2" />
<a attr="test3" />
</item>
<item id="5">
<a attr="test1" />
<a attr="test2" />
</item>
</root>';
SELECT * FROM dbo.ParseXML(@x)
WHERE ItemID=3
GO
ALTER FUNCTION dbo.ParseXML(@xml XML,@ItemID INT)
RETURNS TABLE
AS
RETURN
SELECT item.value('@id','int') AS ItemID
,a.value('@attr','varchar(max)') AS a_Attr
FROM @xml.nodes('/root/item[@id=sql:variable("@ItemID")]') AS One(item)
CROSS APPLY One.item.nodes('a') AS The(a);
GO
DECLARE @x XML=
'<root>
<item id="3">
<a attr="test1" />
<a attr="test2" />
<a attr="test3" />
</item>
<item id="5">
<a attr="test1" />
<a attr="test2" />
</item>
</root>';
SELECT * FROM dbo.ParseXML(@x,5);
GO
CREATE PROCEDURE dbo.ParseXMLDynamically(@xml XML,@ItemID INT)
AS
BEGIN
DECLARE @SqlCmd NVARCHAR(MAX)=
'SELECT item.value(''@id'',''int'') AS ItemID
,a.value(''@attr'',''varchar(max)'') AS a_Attr
FROM @xml.nodes(''/root/item[@id=' + CAST(@ItemID AS VARCHAR(100)) + ']'') AS One(item)
CROSS APPLY One.item.nodes(''a'') AS The(a)';
EXECUTE sp_executesql @SqlCmd,N'@xml XML',@xml;
END
GO
DECLARE @x XML=
'<root>
<item id="3">
<a attr="test1" />
<a attr="test2" />
<a attr="test3" />
</item>
<item id="5">
<a attr="test1" />
<a attr="test2" />
</item>
</root>';
EXEC dbo.ParseXMLDynamically @x, 5;
GO
DROP PROCEDURE dbo.ParseXMLDynamically;
DROP FUNCTION dbo.ParseXML;
关于sql - 直接从用户定义的函数中选择 xml 节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35039518/