php - 从 2 个现有数组创建新数组

Question

我有一个初始日期数组:

Array ( [0] => 2015-11-23 [1] => 2015-11-24 [2] => 2015-11-25 [3] => 2015-11-26 [4] => 2015-11-27 [5] => 2015-11-28 [6] => 2015-11-29 ) 

还有另一个“结果”数组:

Array ( 
   [0] => stdClass Object ( [order_date] => 2015-11-24 [SUM(order_total)] => 1458.5 ) 
   [1] => stdClass Object ( [order_date] => 2015-11-25 [SUM(order_total)] => 1540 ) 
   [2] => stdClass Object ( [order_date] => 2015-11-26 [SUM(order_total)] => 1256 ) 
   [3] => stdClass Object ( [order_date] => 2015-11-27 [SUM(order_total)] => 2516.5 ) 
   [4] => stdClass Object ( [order_date] => 2015-11-28 [SUM(order_total)] => 3436.5 ) )

如何创建一个新数组，该数组返回初始数组中的日期以及结果数组中的相应值(如果存在)，但如果不存在则返回 0？

到目前为止，如果 $dates 是日期数组，$day_of_week_array 是结果数组，我已经尝试过:

foreach ($dates as $date) {
    echo $date."<br>";
        foreach($day_of_week_array as $day_data){
            $day_date = 'order_date';
            $total = 'SUM(order_total)';
            if ($date === $day_of_week_array->$day_date) {
            echo $day_data->$total."<br>";
        }
else { }
}
}

然而，这看起来相当复杂，并且如果日期不匹配(因为数组是嵌套的)，则不允许我返回 0，因此违背了练习的目的。

Answer 1

考虑以下代码:

$result_array = array();
foreach ($dates as $date) {
    $found_flag = 0;
    echo $date."<br>";
    foreach($day_of_week_array as $day_data){
        $day_date = 'order_date';
        $total = 'SUM(order_total)';
        if ($date === $day_of_week_array->$day_date) {
            // echo $day_data->$total."<br>";
            $temp_array = array(
                    'date' => $date,
                    'sum' => $day_data->$total
                );
            array_push($result_array, $temp_array);
            $found_flag = 1;
        }
    }
    if(!$found_flag){
        $temp_array = array(
                'date' => $date,
                'sum' => 0
            );
        array_push($result_array, $temp_array);
    }
}

print_r($result_array); //Your ouptut