sql - 第二列未在 sql 查询中排序，其中我按顺序使用 case 语句

Question

下面的示例查询是我从 stackoverflow 获得的，这很有帮助。我正在使用相同的场景，并且已部分解决。

工作查询

SELECT * 
FROM Requirements
ORDER BY 
     CASE Day 
         WHEN 'Monday' THEN 1
         WHEN 'Tuesday' THEN 2
         WHEN 'Wednesday' THEN 3
         WHEN 'Thursday' THEN 4
         WHEN 'Friday' THEN 5
         WHEN 'Saturday' THEN 6
         WHEN 'Sunday' THEN 7
     END

我的查询输出如下，我的表有重复值，Monday1 在 Monday1 之后返回，但为什么 Tuesday1 在 Tuesday之前返回？

Monday
Monday1
Tuesday1
Tuesday
Wednesday
Wednesday1

我的包含两列值的表格如下所示:

Monday      Monday
Monday      Monday1
Wednesday   Wednesday
Wednesday   Wednesday1
Tuesday     Tuesday
Tuesday     Tuesday1

谢谢。

Answer 1

将包含 Monday1 等的列添加到 ORDER BY 语句中:

;WITH Requirements AS (
SELECT *
FROM (VALUES
('Monday','Monday'),
('Monday','Monday1'),
('Wednesday','Wednesday'),
('Wednesday','Wednesday1'),
('Tuesday','Tuesday'),
('Tuesday','Tuesday1')
) as t([day], col2)
)

SELECT * 
FROM Requirements
ORDER BY 
     CASE Day 
         WHEN 'Monday' THEN 1
         WHEN 'Tuesday' THEN 2
         WHEN 'Wednesday' THEN 3
         WHEN 'Thursday' THEN 4
         WHEN 'Friday' THEN 5
         WHEN 'Saturday' THEN 6
         WHEN 'Sunday' THEN 7
     END , col2

输出:

day         col2
Monday      Monday
Monday      Monday1
Tuesday     Tuesday
Tuesday     Tuesday1
Wednesday   Wednesday
Wednesday   Wednesday1